从程序到产品：将代码转化为可销售的产品

Turning
Your
Code
Into
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"From Program To Product - 转化代码为可销售产品" 本文主要讨论的是将编程成果转化为具有商业价值的产品的过程。作者Barbara Carlton和Rocky Smolin分享了他们的经验，帮助开发者理解如何将代码转变为能够吸引消费者并产生收入的产品。 在编程的世界里，开发出一个功能强大的软件只是第一步。将这个程序转化为一个产品，意味着要考虑更多的方面，如用户体验、市场定位、商业模式、售后服务以及法律问题等。以下是一些关键知识点： 1. 用户体验设计：编程时不仅要关注代码的功能性，还要考虑用户界面(UI)和用户体验(UX)。一个直观、易用的界面可以提高产品的吸引力，增加用户的满意度和留存率。 2. 市场研究：了解目标用户的需求和竞争对手的情况至关重要。这包括对潜在市场进行分析，确定产品的独特卖点（USP），以便在竞争中脱颖而出。 3. 商业模型：思考如何通过产品盈利，例如是采用一次性购买、订阅制还是广告支持的模式。此外，定价策略也是商业模型的一部分，需要与产品价值和市场接受度相匹配。 4. 营销策略：有效的营销可以帮助产品获得曝光，建立品牌认知。这可能包括社交媒体推广、内容营销、合作伙伴关系等。 5. 法律合规：确保产品符合所有适用的法律法规，包括版权、数据保护、隐私权和许可证规定。了解并遵守这些规定可以避免潜在的法律纠纷。 6. 版本控制和持续集成：在产品开发过程中，采用版本控制系统（如Git）有助于团队协作和代码管理。持续集成/持续部署(CI/CD)则可以确保代码的稳定性和质量。 7. 测试与反馈：在产品推出前进行充分的测试，包括单元测试、集成测试和用户验收测试，以发现并修复问题。收集用户反馈，不断迭代和优化产品，以满足市场需求。 8. 售后服务和技术支持：提供良好的客户服务和技术支持可以增强用户信任，提升产品的口碑。这可能包括在线帮助文档、社区论坛、电话支持等。 9. 扩展性与可维护性：设计时应考虑到产品的未来扩展，使其易于维护和升级，以适应市场的变化。 10. 代码质量与文档：编写高质量、可读性强的代码，并提供详细的文档，这将使产品更易于维护和合作开发，同时也能吸引其他开发者参与和贡献。 "From Program To Product" 是一个全面探讨将编程作品转变为商业产品的过程，涵盖了从技术实现到市场营销，再到法律合规等多个层面。通过学习这些知识，开发者可以更好地理解如何将他们的代码转化为成功的商业产品。

From Project to Product Turning Your Code into a Saleable Product.pdf

2008-05-07 上传
This book is really about getting to your first day in business.It is about taking that raw idea you have for a program and creating asaleable product. And setting up the support systems you need to make yourbusiness hum.8 Chapter 1 Who Wants to Be a Millionaire?If you’re going to do this thing, you have to be ready for some tough days.But nothing worthwhile ever comes easy. Sometimes what it really takes is stupid,blind obstinacy—the drive to keep going, stubbornly solving one problemat a time until you get the brass ring.Once I had a partner who had one of those ghastly motivational postershung in our office. You know, the kind that promotes leadership and teamworkand quality through the use of tired old clichés and kitschy art. This one wasno exception. And yet its corny McCuen-esque message stuck in my mind andhas provided a handy boost to me many times over the years. It was a pictureof a three-masted sailing ship threading its way between rocky outcroppingand small islands. And the message:

HY27UT088G2M

2012-05-31 上传
19, 2006)**: Updates included adding an ECC algorithm (4-bit/528 bytes) and changing AC characteristics, such as the program time from 600 us to 800 us. - **Revision 0.2 (Nov. 30, 2006)**: This ...

写一个程序满足以下要求a) Document that a program calculates the product of three integers. b) Declare the variables x, y, z and result to be of type int (in separate statements) and initialize each to 0. c) Prompt the user to enter three integers. d) Read three integers from the keyboard and store them in the variables x, y and z. e) Compute the product of the three integers contained in variables x, y and z, and assign the result to the variable result. f) Print "The product is " followed by the value of the variable result. g) Return a value from main indicating that the program terminated successfully.

2023-05-30 上传
// This program calculates the product of three integers. #include int main() { // Declare variables and initialize them to 0. int x = 0; int y = 0; int z = 0; int result = 0; // Prompt the ...

Write a program to manage inventory of goods. The specific functions are: (1) Enter the quantity of products and the name, number, and inventory quantity of each product through the keyboard. (2) Save the inventory quantity of the product to a text file. (3) Read the document and print product information in descending order of inventory for the product.use c++

2023-06-06 上传
The program provides a menu with options to add a product, save the inventory to a file, load the inventory from a file, print the inventory, and exit the program. The program uses `fstream` to read ...

(Telephone Number Word Generator) Standard telephone keypads contain the digits 0 through 9. The numbers 2 through 9 each have three letters associated with them, as is indicated by the following table: Many people find it difficult to memorize phone numbers, so they use the correspondence between digits and letters to develop seven-letter words that correspond to their phone numbers. For example, a person whose telephone number is 686-2377 might use the correspondence indi- cated in the above table to develop the seven-letter word “NUMBERS.” Businesses frequently attempt to get telephone numbers that are easy for their clients to remember. If a business can advertise a simple word for its customers to dial, then no doubt the business will receive a few more calls. Each seven-letter word corresponds to exactly one seven-digit telephone number. The restaurant wishing to increase its take-home business could surely do so with the number 825-3688 (i.e., “TAKEOUT”). Each seven-digit phone number corresponds to many separate seven-letter words. Unfortunately, most of these represent unrecognizable juxtaposi- tions of letters. It’s possible, however, that the owner of a barber shop would be pleased to know that the shop’s telephone number, 424-7288, corresponds to “HAIRCUT.” A veterinarian with the phone number 738-2273 would be happy to know that the number corresponds to “PETCARE.” Write a program that, given a seven-digit number, writes to a file every possible seven-letter word corresponding to that number. There are 2187 (3 to the seventh power) such words. Avoid phone numbers with the digits 0 and 1.

2023-06-09 上传
Here's a Python program to generate all possible seven-letter words corresponding to a given seven-digit phone number: ```python import itertools # mapping of digits to letters digit_to_letter = { ...

write a C program to calculate the multiplication of two matrices using two_dimensional array. Requirement Getting input from users

2023-06-10 上传
printf("Product of the matrices:\n"); for (c = 0; c ; c++) { for (d = 0; d ; d++) printf("%d\t", multiply[c][d]); printf("\n"); } } return 0; } ``` 该程序通过提示用户输入每个矩阵的行和列数...

Java(Algebra: perfect square) Write a program that prompts the user to enter an integer m and find the smallest integer n such that m * n is a perfect square. (Hint: Store all smallest factors of m into an array list. n is the product of the factors that appear an odd number of times in the array list. For example, consider m = 90, store the factors 2, 3, 3, and 5 in an array list. 2 and 5 appear an odd number of times in the array list. Thus, n is 10.) Here are some sample runs: Enter an integer m: 1500 The smallest number n for m * n to be a perfect square is 15 m * n is 22500

2023-05-24 上传
Here's the Java program to solve the problem: ```java import java.util.ArrayList; import java.util.Scanner; public class PerfectSquare { public static void main(String[] args) { Scanner input = ...

用c语言代码写九九乘法表

2023-03-24 上传
The outer loop iterates from 1 to 9, and the inner loop iterates from 1 to the current value of the outer loop variable. Inside the inner loop, we print the product of the two loop variables, along ...

A factory produces products packed in square packets of the same height $h$ and of the sizes $1 \times 1, 2 \times 2, 3 \times 3, 4 \times 4, 5 \times 5, 6 \times 6$. These products are always delivered to customers in the square parcels of the same height $h$ as the products have and of the size $6 \times 6$. Because of the expenses it is the interest of the factory as well as of the customer to minimize the number of parcels necessary to deliver the ordered products from the factory to the customer. A good program solving the problem of finding the minimal number of parcels necessary to deliver the given products according to an order would save a lot of money. You are asked to make such a program. c++

2023-06-01 上传
bool cmp(const Product& a, const Product& b) { return a.count > b.count_random_iter: # 如果使用随机采样，在每个小批量更新前初始化隐藏状态 state = model.init; } int minBoxes(vector<Product>& ...

用C语言超市信息管理系统 功能要求: 1.每一条记录包括一个商品的编号，名称，价格，条形码，进货日期。库存，销售数量。 2.输入功能:可以一次完成若干条记录的输入。 3.显示功能:完成全部记录的显示。 4.查找功能:用折半查找完成按商品编号查找记录并显示。 5.排序功能:用希尔排序按销售数量从高到低或者按照商品编号进行排序。 6. 插入功能:按编号插入一条记录。 7.将记录保存在文件中。 8. 应提供一个菜单来调用各个功能，调用菜单的界面应尽可能清晰美观。 9.删除功能 10.修改功能 11.代码要有亮点，并且将代码展示出来

2023-05-25 上传
printf("\nEnter product ID to search for: "); scanf("%d", &id); int left = 0; int right = count - 1; int found = 0; while (left ) { int mid = (left + right) / 2; if (products[mid].id == id) {...
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