提升课堂作业完成度与准确性的日常报告卡策略

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本文档探讨了"提高课堂作业完成度和准确性：每日报告卡程序的应用"的主题，发表于《心理学与学校》(Psychoiogy in the Schools)第19卷，1982年10月刊。作者Barry M. Drew来自儿童服务中心，而Joseph H. Evans、Darrel E. Bostow、Glenn Geiger和Philip W. Drash则来自佛罗里达大学。 研究背景中指出，尽管已经证实家内强化技术在减少课堂上的一些问题行为如扰乱行为方面颇具成效，但关于利用这些方法提升学生在学校内的积极表现，特别是提高作业完成度和准确性方面的研究相对较少。本论文旨在考察一种名为"每日报告卡程序"的策略，该程序特别设计用于帮助两个被描述为有困难完成课堂作业行为的学生。 实验对象是两名存在行为问题，难以按时且准确完成课后作业的小学生。通过实施每日报告卡程序，研究人员观察到了显著的即时变化，即参与者的作业完成率和准确性都有所提高。这项研究强调了家校合作在提升学生学术表现中的作用，并探讨了这种方法的有效性和可能遇到的问题。 文章的重点在于介绍每日报告卡程序的操作细节，可能包括定期评估学生的作业进度，家长根据完成情况给予正面反馈或奖励，以及如何调整程序以适应不同个体的学习需求。同时，它也反思了如何将这种策略扩展到更广泛的教育环境中，以解决普遍存在的小学生作业难题。 这篇论文提供了关于通过日常教学管理工具提升学生学习效率和责任感的重要见解，对于教育实践者和政策制定者来说，是一个有价值的参考资源，特别是对于那些关注课堂纪律和学业成绩提升的教师和家长。

使用每日报告卡程序提高作业完成度和准确性

2021-06-29 上传
Increasing assignment completion and accuracy using a daily report card procedure Psychoiogy In ihe Schools Volume 19. October. 1982 INCREASING ASSIGNMENT COMPLETION AND ACCURACY USING A DAILY ...

Write a generator function merge that takes in two infinite generators a and b that are in increasing order without duplicates and returns a generator that has all the elements of both generators, in increasing order, without duplicates.

2023-06-01 上传
This generator function takes two infinite generators `a` and `b` that are in increasing order without duplicates, and returns a generator that has all the elements of both generators, also in ...

帮我看看这段话有没有语法错误：The first effect of guaranteeing people have basic financial products and services is increasing the overall quality of people’s lives. Ensuring reliable access to financial products and services can contribute to helping families and companies plan the future from two aspects, long-term goals and unexpected emergencies (The World Bank, 2022). Long-term goals mean long-term investments such as investments in health: saving money against illness, saving for a child’s education, saving for a house or car, etc. Unexpected emergencies mean managing risk, that is, people can apply for a loan from the bank when they are in the face of a sudden bankruptcy or business shock. Furthermore, when people meet weather financial shocks, the government and banks will give some financial assistance. With these financial services, people have a basic guarantee of life and a clear plan for the future in the meanwhile. Guarantee of financial services leads them to save a sum of money in a safe bank account for buying a house, providing funds for children’s education, and buying medical insurance for both themselves and their families to prevent the sudden arrival of diseases. In daily life, online payment improves life efficiency such as reducing queuing time. Additionally, in occupational life, financial guarantees can encourage and empower young people can be bolder to pursue their entrepreneurial dreams by providing them with start-up funds from banks. All in all, the guarantee of financial products leads to individuals plan for their financial futures and improve their overall quality of life.

2023-05-05 上传
1. "The first effect of guaranteeing people have basic financial products and services is increasing the overall quality of people’s lives." 可以改为 "The first effect of guaranteeing that people ...

### Problem 4: Merge Write a generator function `merge` that takes in two infinite generators `a` and `b` that are in increasing order without duplicates and returns a generator that has all the elements of both generators, in increasing order, without duplicates. > **Note:** You may assume that both `a` and `b` contains unlimited elements. As a result, calling `next(a)` and `next(b)` will never throw `StopIteration` exception. ```python def merge(a, b): """Merge two generators that are in increasing order and without duplicates. Return a generator that has all elements of both generators in increasing order and without duplicates. >>> def sequence(start, step): ... while True: ... yield start ... start += step >>> a = sequence(2, 3) # 2, 5, 8, 11, 14, ... >>> b = sequence(3, 2) # 3, 5, 7, 9, 11, 13, 15, ... >>> result = merge(a, b) # 2, 3, 5, 7, 8, 9, 11, 13, 14, 15 >>> [next(result) for _ in range(10)] [2, 3, 5, 7, 8, 9, 11, 13, 14, 15] """ "*** YOUR CODE HERE ***"

2023-06-02 上传
Merge two generators that are in increasing order and without duplicates. Return a generator that has all elements of both generators in increasing order and without duplicates. """ a_val = next...

Show how to modify the PRINT_STATIONS procedure to print out the stations in increasing order of station number. (Hint: Use recursion)

2023-05-31 上传
Here's one way to modify the PRINT_STATIONS procedure to print out the stations in increasing order of station number using recursion: ``` PROCEDURE PRINT_STATIONS (S: STATION_LIST); VAR I: INTEGER...

Write a function with the declaration: smoothed=rectFilt(x,width). The filter should take a vector of noisy data (x) and smooth it by doing a symmetric moving average with a window of the specified width. For example if width=5, then smoothed(n) should equal mean(x(n-2:n+2)). Note that you may have problems around the edges: when n<3 and n>length(x)-2. a. The lengths of x and smoothed should be equal. b. For symmetry to work, make sure that width is odd. If it isn’t, increase it by 1 to make it odd and display a warning, but still do the smoothing. c. Make sure you correct edge effects so that the smoothed function doesn’t deviate from the original at the start or the end. Also make sure you don’t have any horizontal offset between the smoothed function and the original (since we’re using a symmetric moving average, the smoothed values should lie on top of the original data). d. You can do this using a loop and mean (which should be easy but may be slow), or more efficiently by using conv (if you are familiar with convolution). e. Load the mat file called noisyData.mat. It contains a variable x which is a noisy line. Plot the noisy data as well as your smoothed version, like below (a width of 11 was used):

2023-06-07 上传
%RECTFILT Smooths a vector of noisy data using a symmetric moving average with a specified window width. % smoothed = rectFilt(x, width) returns a vector that is the same size as x, where each element...

Write a procedure div-series that divides two power series. div-series should work for any two series, provided that the denominator series begins with a non-zero constant term. (If the denominator has a zero constant term, then div-series should signal an error.) You may find it useful to reuse some answer from a previous exercise in this problem set. Turn in a listing of your procedure along with three or four wellchosen test cases (and demonstrate why the answers given by your division are indeed the correct answers)（piease use lisp）

2023-06-06 上传
In test case 3, we divide the series `(1 + x + x^2)` by the series `(1 - x)`, which should result in a series of increasing integers. In test case 4, we divide the series `(1 + x + x^2)` by itself, ...

Implement time_per_word, which takes in times_per_player, a list of lists for each player with timestamps indicating when each player finished typing each word. It also takes in a list words. It returns a game with the given information. A game is a data abstraction that has a list of words and times. The times are stored as a list of lists of how long it took each player to type each word. times[i][j] indicates how long it took player i to type word j. For example, if times_per_player = [[1, 3, 5], [2, 5, 6]], the corresponding time attribute of the game would be [[2, 2], [3, 1]]. Timestamps are cumulative and always increasing, while the values in time are differences between consecutive timestamps. Be sure to use the game constructor when returning a game, rather than assuming a particular data format.Given timing data, return a game data abstraction, which contains a list of words and the amount of time each player took to type each word. Arguments: times_per_player: A list of lists of timestamps including the time the player started typing, followed by the time the player finished typing each word. words: a list of words, in the order they are typed.

2023-06-01 上传
Note that this implementation assumes that all players typed the same set of words in the same order, and that the timestamps are cumulative and increasing (i.e., the time to type each word is always ...

Applying Lasso Regularization method and will try to increase accuracy of model

2023-06-08 上传
By increasing the value of alpha, some of the coefficients are set to zero, leading to a simpler model that is less prone to overfitting. To apply Lasso regularization to your model, you can use the...

You are given strictly increasing sequences of length N and M: A=(A 1 ​ ,A 2 ​ ,…,A N ​ ) and B=(B 1 ​ ,B 2 ​ ,…,B M ​ ). Here, A i ​  =B j ​ for every i and j (1≤i≤N,1≤j≤M). Let C=(C 1 ​ ,C 2 ​ ,…,C N+M ​ ) be a strictly increasing sequence of length N+M that results from the following procedure. Let C be the concatenation of A and B. Formally, let C i ​ =A i ​ for i=1,2,…,N, and C i ​ =B i−N ​ for i=N+1,N+2,…,N+M. Sort C in ascending order. For each of A 1 ​ ,A 2 ​ ,…,A N ​ ,B 1 ​ ,B 2 ​ ,…,B M ​ , find its position in C. More formally, for each i=1,2,…,N, find k such that C k ​ =A i ​ , and for each j=1,2,…,M, find k such that C k ​ =B j ​ . Constraints 1≤N,M≤10 5 1≤A 1 ​ <A 2 ​ <⋯<A N ​ ≤10 9 1≤B 1 ​ <B 2 ​ <⋯<B M ​ ≤10 9 A i ​  =B j ​ for every i and j (1≤i≤N,1≤j≤M). All values in the input are integers.c++代码

2023-03-20 上传
int *a = (int*)malloc(n * sizeof(int)); int *b = (int*)malloc(m * sizeof(int)); for (int i = 0; i ; i++) { scanf("%d", &a[i]); } for (int i = 0; i ; i++) { scanf("%d", &b[i]); } int *c = ...
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