python实现关于一元二次方程的公式求解的所有情况 (包括不同实根、相同实根、共钜复根)

以下是 Python 实现一元二次方程的公式求解的所有情况的代码：

import math

def solve_quadratic_equation(a, b, c):
    delta = b**2 - 4*a*c
    if delta > 0:
        x1 = (-b + math.sqrt(delta)) / (2*a)
        x2 = (-b - math.sqrt(delta)) / (2*a)
        return "两个不同的实根：x1 = {}, x2 = {}".format(x1, x2)
    elif delta == 0:
        x = -b / (2*a)
        return "一个实根：x = {}".format(x)
    else:
        real_part = -b / (2*a)
        imag_part = math.sqrt(-delta) / (2*a)
        return "共轭复根：x1 = {}+{}i, x2 = {}-{}i".format(real_part, imag_part, real_part, imag_part)

# 测试
print(solve_quadratic_equation(1, 2, 1))  # 一个实根：x = -1.0
print(solve_quadratic_equation(1, -3, 2))  # 两个不同的实根：x1 = 2.0, x2 = 1.0
print(solve_quadratic_equation(1, 2, 3))  # 共轭复根：x1 = -1.0+1.4142135623730951i, x2 = -1.0-1.4142135623730951i

希望这个代码能够帮助你解决问题！