输入两个二维平面向量V1=(x1,y1)、V2=(x2,y2)的分量，计算并输出两个向量的和向量，即V=(x1+x2,y1+y2)。 例如输入： 3.5 -2.7 -13.9 8.7 输出： -10.4 6.0 函数接口定义： struct vector sum(struct vector v1,struct vector v2); 裁判测试程序样例： #include "stdio.h" struct vector{ double x; double y; }; struct vector sum(struct vector v1,struct vector v2); int main(void) { struct vector v, v1, v2; scanf ("%lf%lf%lf%lf", &v1.x, &v1.y, &v2.x, &v2.y); v=sum(v1,v2); printf("%.1f %.1f\n", v.x, v.y); return 0; } /* 请在这里填写答案 */

break;

case 2:
float subjectAverages[MAX_SUBJECTS] = {0};
float classAverages[MAX_SUBJECTS] = {0};
int classCounts[MAX_SUBJECTS] = {0};
float totalAverage = 0;
int totalCount您可以使用以下代码来实现计算并输出两个向量的和向量：

#include "stdio.h"

struct vector {
= 0;

for (int i = 0; i < numStudents; i++) {
for (int j = 0 double x;
double y;
};

struct vector sum(struct vector v1, struct vector v2) {
struct vector result;
; j < MAX_SUBJECTS; j++) {
subjectAverages[j] += students[i].subjects[j];
classAverages[j result.x = v1.x + v2.x;
result.y = v1.y + v2.y;
return result;
}

int] += students[i].subjects[j];
classCounts[j]++;
totalAverage += students[i].subjects[j];
totalCount++;
}
main(void) {
struct vector v, v1, v2;
scanf("%lf%lf%lf%lf", &v1 }

printf("\n----- 各班各门课程平均成绩 -----\n");

for (int i = 0.x, &v1.y, &v2.x, &v2.y);
v = sum(v1, v2);
printf("%.1f %.1f\n", v.x, v.y);
return 0;
}