Error-[SE] Syntax error Following verilog source has syntax error : Token 'goto' not recognized as a type. Please check whether it is misspelled, not visible/valid in the current context, or not properly imported/exported. This is occurring in a context where a variable declaration, a statement, or a sequence expression is expected. Either the declaration type is not known or this is incorrect syntax. "vector.v", 60: token is ';' goto deleted_vector;报错怎么办
时间: 2023-07-02 09:12:20 浏览: 195
Verilog中不支持使用goto语句,所以出现了Syntax error,你需要修改你的代码。你可以使用if语句或case语句,以实现类似的跳转功能。你的代码中的goto语句可以改为如下的代码:
```
if (condition) begin
deleted_vector <= 1'b1;
end
```
或者
```
case (condition)
true: deleted_vector <= 1'b1;
default: deleted_vector <= 1'b0;
endcase
```
这些代码可以实现类似于goto语句的功能,但是不会出现Syntax error。
相关问题
Error-[SE] Syntax error Following verilog source has syntax error : "count.v", 26: token is 'endmodule'
这个错误是因为在 Verilog 中,每个模块定义必须以 "endmodule" 关键字结束。在你的代码中,第 26 行没有 "endmodule" 关键字,导致出现了语法错误。
正确的代码应该是:
```verilog
module count(
input clk,
input rst,
output reg [6:0] out
);
always @(posedge clk, posedge rst) begin
if(rst) begin
out <= 7'b0;
end else begin
out <= out + 1;
end
end
endmodule
```
请注意,以上代码加了缺少的 "endmodule" 关键字,并且将 "out" 的位宽修改为 6,以匹配你的代码中的输出端口。
Error-[SE] Syntax error Following verilog source has syntax error : "./rtl/fifo.v", 2: token is 'parameter' parameter WIDTH = 32,
The Verilog code you provided indicates a syntax error on the second line of the file "./rtl/fifo.v". The error message states that the token "parameter" is causing the issue.
Without seeing the rest of the code, my best guess is that the parameter declaration is missing a semicolon at the end of the line. Here's an example of what the corrected line may look like:
```
parameter WIDTH = 32;
```
Make sure to check the rest of the code for any other syntax errors, as they may also be contributing to the issue.