#include <iostream> using namespace std; class A { public: A(int a = 0, int b = 0) : x(a), y(b) { } friend A operator + (const A &x1, const A &x2); // ①请根据程序修改其中错误 friend ostream&operator << ( const A&out, const A &c); // ②请根据程序修改其中错误 private: int x, y; }; A operator + (const A &x1, const A &x2) { return A(x1.x + x2.x, x1.y + x2.y); } ostream&operator << (const A &out, const A &c) { // ③请根据程序修改其中错误 out << "(" << c.x << ", " << c.y << ")"; return out; // ④请根据程序修改其中错误 } int main() { A x1(5, 4), x2(2, 10), x3; x3 = x1 + x2; cout << "x3 = x1 + x2 = " << x3 << endl; return 0; }怎么改错
时间: 2024-02-06 20:03:37 浏览: 73
在这段程序中,有以下错误需要修改:
① `operator +` 函数的定义缺少类名 `A` 的限定符,应改为:
```cpp
A A::operator + (const A &x1, const A &x2) {
return A(x1.x + x2.x, x1.y + x2.y);
}
```
② `operator<<` 函数的定义缺少类名 `A` 的限定符,应改为:
```cpp
ostream& operator << (ostream &out, const A &c) {
out << "(" << c.x << ", " << c.y << ")";
return out;
}
```
③ 在 `operator<<` 函数的实现中,参数名 `out` 和函数体内的 `out` 发生了重名,应将其中一个修改为其他名称,例如:
```cpp
ostream& operator << (ostream &os, const A &c) {
os << "(" << c.x << ", " << c.y << ")";
return os;
}
```
④ 在 `operator<<` 函数的实现中,应该返回 `ostream&` 类型的对象,而不是 `A&` 类型,应改为:
```cpp
ostream& operator << (ostream &out, const A &c) {
out << "(" << c.x << ", " << c.y << ")";
return out;
}
```
修改后的完整程序如下:
```cpp
#include <iostream>
using namespace std;
class A {
public:
A(int a = 0, int b = 0) : x(a), y(b) { }
friend A operator + (const A &x1, const A &x2);
friend ostream& operator << (ostream &out, const A &c);
private:
int x, y;
};
A A::operator + (const A &x1, const A &x2) {
return A(x1.x + x2.x, x1.y + x2.y);
}
ostream& operator << (ostream &out, const A &c) {
out << "(" << c.x << ", " << c.y << ")";
return out;
}
int main() {
A x1(5, 4), x2(2, 10), x3;
x3 = x1 + x2;
cout << "x3 = x1 + x2 = " << x3 << endl;
return 0;
}
```
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