将pygame打地鼠封装成函数

好的，下面是一个简单的将 Pygame 打地鼠游戏封装成函数的示例代码：

import pygame
import random

def play_whack_a_mole():
    # 初始化 Pygame
    pygame.init()

    # 设置游戏窗口大小
    window_size = (640, 480)
    screen = pygame.display.set_mode(window_size)

    # 设置游戏标题
    pygame.display.set_caption('Whack-a-Mole')

    # 加载图片资源
    mole_image = pygame.image.load('mole.png')
    mole_hit_image = pygame.image.load('mole_hit.png')
    hammer_image = pygame.image.load('hammer.png')

    # 设置游戏参数
    mole_size = mole_image.get_size()
    mole_hit_size = mole_hit_image.get_size()
    hammer_size = hammer_image.get_size()

    mole_speed = 5
    mole_spawn_time = 1500
    mole_spawn_timer = 0
    mole_spawned = False
    mole_x, mole_y = 0, 0

    hammer_x, hammer_y = 0, 0
    hammer_visible = False

    score = 0

    # 设置游戏循环
    running = True
    clock = pygame.time.Clock()

    while running:
        # 处理事件
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                running = False
            elif event.type == pygame.MOUSEBUTTONDOWN:
                if hammer_visible:
                    hammer_rect = pygame.Rect(hammer_x, hammer_y, hammer_size[0], hammer_size[1])
                    if hammer_rect.collidepoint(pygame.mouse.get_pos()):
                        score += 1
                        hammer_visible = False

        # 更新游戏状态
        mole_spawn_timer += clock.get_time()
        if not mole_spawned and mole_spawn_timer > mole_spawn_time:
            mole_x = random.randint(0, window_size[0] - mole_size[0])
            mole_y = random.randint(0, window_size[1] - mole_size[1])
            mole_spawned = True
            mole_spawn_timer = 0

        if mole_spawned:
            mole_y += mole_speed
            if mole_y > window_size[1]:
                mole_spawned = False

        if not hammer_visible:
            hammer_x, hammer_y = pygame.mouse.get_pos()
            hammer_x -= hammer_size[0] // 2
            hammer_y -= hammer_size[1] // 2

        # 绘制游戏界面
        screen.fill((255, 255, 255))

        if mole_spawned:
            screen.blit(mole_image, (mole_x, mole_y))
        else:
            mole_spawned = False

        if hammer_visible:
            screen.blit(hammer_image, (hammer_x, hammer_y))

        if score > 0:
            font = pygame.font.Font(None, 36)
            text = font.render(f'Score: {score}', True, (0, 0, 0))
            screen.blit(text, (10, 10))

        # 更新屏幕显示
        pygame.display.flip()

        # 控制游戏帧率
        clock.tick(60)

    # 退出 Pygame
    pygame.quit()

使用该函数，只需要在你的 Python 代码中调用 `play_whack_a_mole()` 即可开始游戏。请注意，该示例代码需要保证当前工作目录下存在名为 `mole.png`、`mole_hit.png` 和 `hammer.png` 的图片资源文件。您可以根据自己的需求修改函数参数和游戏设置。