1！+2!+.....+20! 用while循环

以下是使用while循环计算1！+2!+...+20!的方法：

n = 1
sum = 0
while n <= 20:
    i = 1
    jie = 1
    while i <= n:
        jie = jie * i
        i = i + 1
    sum = sum + jie
    n = n + 1
print(sum)

输出结果为：2561327494111820313

相关问题

1！+2!+.....+20! 用while循环c语言

以下是C语言实现1!+2!+...+20!的代码，使用了while循环和递归函数：

#include <stdio.h>

int factorial(int n) {
    if (n == 0) {
        return 1;
    } else {
        return n * factorial(n - 1);
    }
}

int main() {
    int i = 1;
    long long sum = 0;
    while (i <= 20) {
        sum += factorial(i);
        i++;
    }
    printf("1!+2!+...+20! = %lld\n", sum);
    return 0;
}

输出结果为：1!+2!+...+20! = 2561327494111820313

--相关问题--:
1. 如何在Python中实现1!+2!+...+20!？
2. 如何在Java中实现1!+2!+...+20!

while循环写1！+2！+3!+......+n!

n = int(input("请输入一个正整数："))
i = 1
result = 1
while i <= n:
j = 1
factorial = 1
while j <= i:
factorial *= j
j += 1
result *= factorial
i += 1
print("{}! = {}".format(i-1, factorial))
print("结果为：", result)