可以利用Domain-Independent Dynamic Programming解决预制构件流水车间的订单接收问题吗,帮我写一份可以运行的完整代码,要求解释详细
时间: 2024-10-12 17:10:07 浏览: 16
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是的,我们可以利用Domain-Independent Dynamic Programming (DIDP) 的策略来优化预制构件流水车间的订单接收问题。这种动态规划方法通常适用于那些有结构化的子问题并且最优解依赖于子问题最优解的问题。在这种场景下,流水线的任务分配和调度问题可以看作是子问题空间的搜索。
以下是简化的伪代码示例,它并不直接提供完整的运行代码,因为实际代码会根据具体的生产环境、约束条件和数据结构有所不同。假设我们有一个工厂模型,其中包含订单、工位和时间单位:
```python
# 定义基础数据结构
class Order:
def __init__(self, id, components):
self.id = id
self.components = components
class Workstation:
def __init__(self, capacity):
self.capacity = capacity
self.free_capacity = capacity
# DIDP函数,接收订单列表、工作站列表等参数
def didp_orders(received_orders, workstations, time_units):
# 初始化二维动态规划表
dp = [[0] * len(workstations) for _ in range(len(time_units))]
# 动态规划状态转移方程
def transition(prev_time_unit, prev_workstation, current_order):
if prev_workstation.free_capacity < current_order.components or prev_time_unit == time_units[-1]:
return float('inf') # 非法操作或无法完成订单
else:
new_state = dp[prev_time_unit][prev_workstation.id]
return min(new_state,
didp_orders(current_order.id,
workstations,
time_units[prev_time_unit + 1]) +
current_order.components)
# 搜索过程,从第一个订单开始
for order in received_orders:
dp[0][0] = transition(0, 0, order)
# 返回最短总时间
return dp[-1][-1]
# 示例用法
received_orders = [Order(1, 5), Order(2, 3)]
workstations = [Workstation(10)] # 假设每个工作站都有足够大容量
time_units = list(range(len(received_orders))) # 时间单位对应订单顺序
optimal_time = didp_orders(received_orders, workstations, time_units)
print(f"Optimal completion time is {optimal_time} time units.")
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