用case实现round robin 4路verilog实现 与tb文件
时间: 2023-08-31 09:10:28 浏览: 89
4路组cache,verilog实现
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以下是Round Robin 4路Verilog实现:
```verilog
module round_robin_4(input clk, input reset, input [3:0] request, output reg [3:0] grant);
reg [1:0] counter;
always @(posedge clk) begin
if (reset) begin
counter <= 2'b00;
grant <= 4'b0001;
end
else begin
// Check for requests
if (request != 4'b0000) begin
// Load counter
counter <= counter + 2'b01;
// Check for overflow
if (counter == 2'b11) begin
counter <= 2'b00;
end
// Check for requests
if (request[counter]) begin
grant <= {grant[2:0], grant[3]};
end
end
end
end
endmodule
```
以下是Round Robin 4路Testbench文件:
```verilog
`timescale 1ns / 1ps
module round_robin_4_tb;
reg clk;
reg reset;
reg [3:0] request;
wire [3:0] grant;
round_robin_4 dut (
.clk(clk),
.reset(reset),
.request(request),
.grant(grant)
);
initial begin
clk = 0;
reset = 1;
request = 4'b0000;
#10 reset = 0;
#10 request = 4'b0001;
#10 request = 4'b0010;
#10 request = 4'b0100;
#10 request = 4'b1000;
#10 request = 4'b0011;
#10 request = 4'b0110;
#10 request = 4'b1100;
#10 request = 4'b1010;
#10 request = 4'b1111;
#10 request = 4'b0000;
#10 $finish;
end
always #5 clk = ~clk;
endmodule
```
在testbench中,我们将request信号逐个设置为4个输入端口的请求。您可以根据需要更改此测试向量。
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