N = int(input()) for n in range(1,N+1): if isPrime(n) and reverseNumber(n) == n: 回文素数是指一个数既是素数又是回文数。例如，131，既是素数又是回文数。 用户输入一个正整数 n , 请你在一行内输出从小到大排列的的前n个回文素数，数字后面用一个空格进行分隔

Sure! Here's a Python code snippet that can help you find and display the first N palindromic prime numbers:

def isPrime(num):
    if num < 2:
        return False
    for i in range(2, int(num ** 0.5) + 1):
        if num % i == 0:
            return False
    return True

def reverseNumber(num):
    rev = 0
    while num > 0:
        rev = rev * 10 + num % 10
        num = num // 10
    return rev

N = int(input())
count = 0
num = 2

while count < N:
    if isPrime(num) and reverseNumber(num) == num:
        print(num, end=" ")
        count += 1
    num += 1

You can use this code to find the first N palindromic prime numbers. Just remember to replace `input()` with the appropriate way of taking user input in your specific programming environment.

Let me know if you need any further assistance!