for i, row in (len(x)): TypeError: 'int' object is not iterable
时间: 2023-10-27 15:38:38 浏览: 37
This error occurs when you try to iterate over an integer value, which is not iterable. In the given code, the line "for i, row in (len(x))" is causing the error because you are trying to iterate over the length of x, which is an integer value.
To fix this error, you need to iterate over an iterable object such as a list or a tuple. For example, if x is a list of lists, you can iterate over it as follows:
for i, row in enumerate(x):
# do something with row
Here, the enumerate() function returns a tuple of index i and row, which you can use in your loop.
相关问题
for i in len(keywords): TypeError: 'int' object is not iterable
这错误是因为在 `for` 循环的 `range` 函数中传入了一个整数,而 `range` 接受的是一个可迭代的对象,例如一个列表或一个迭代器。你可以将 `range(len(keywords))` 传给 `for` 循环来遍历 `keywords` 列表的索引,或者直接使用 `for keyword in keywords` 遍历 `keywords` 列表中的元素。以下是两个示例:
使用索引:
```
keywords = ['foo', 'bar', 'baz']
for i in range(len(keywords)):
print(i, keywords[i])
```
直接遍历元素:
```
keywords = ['foo', 'bar', 'baz']
for keyword in keywords:
print(keyword)
```
for k in kernels: TypeError: 'int' object is not iterable
这个错误通常是因为你将一个整数对象传递给了需要迭代的函数或方法。例如,在这个错误中,`kernels` 可能是一个整数,而你尝试在 `for` 循环中迭代它。请确保 `kernels` 是一个可迭代的对象,例如列表或元组。
如果 `kernels` 是一个整数,你可以将其转换为一个包含该整数的列表,然后再进行迭代。例如:
```
kernels = 3
for k in [kernels]:
# do something with k
```
如果 `kernels` 是一个列表或元组,那么请检查它是否被正确地定义和初始化。