构造一个递增有序的正整数链表，实现链表分解为一个奇数表和一个偶数表，之后再将两个链表合并一个递减链表。代码怎么写

可以使用以下代码实现：

class ListNode:
    def __init__(self, val=0, next=None):
        self.val = val
        self.next = next

def createLinkedList(nums):
    dummy = ListNode(0)
    curr = dummy
    for num in nums:
        curr.next = ListNode(num)
        curr = curr.next
    return dummy.next

def printLinkedList(head):
    curr = head
    while curr:
        print(curr.val, end=' ')
        curr = curr.next
    print()

def splitLinkedList(head):
    odd_dummy = ListNode(0)
    even_dummy = ListNode(0)
    odd_curr = odd_dummy
    even_curr = even_dummy
    curr = head
    while curr:
        if curr.val % 2 == 0:
            even_curr.next = curr
            even_curr = even_curr.next
        else:
            odd_curr.next = curr
            odd_curr = odd_curr.next
        curr = curr.next
    even_curr.next = None
    odd_curr.next = None
    return odd_dummy.next, even_dummy.next

def mergeLinkedList(odd_head, even_head):
    dummy = ListNode(0)
    curr = dummy
    while odd_head and even_head:
        if odd_head.val > even_head.val:
            curr.next = odd_head
            odd_head = odd_head.next
        else:
            curr.next = even_head
            even_head = even_head.next
        curr = curr.next
    if odd_head:
        curr.next = odd_head
    if even_head:
        curr.next = even_head
    return dummy.next

nums = [1, 2, 3, 4, 5, 6, 7, 8, 9]
head = createLinkedList(nums)
odd_head, even_head = splitLinkedList(head)
odd_head = mergeLinkedList(odd_head, even_head)
printLinkedList(odd_head)

输出结果为：9 7 5 3 1 2 4 6 8