写一个python扫雷游戏
时间: 2023-08-25 21:53:41 浏览: 127
当然,我可以帮你编写一个简单的Python扫雷游戏。以下是一个基本的实现示例:
```python
import random
# 游戏板大小
board_size = 10
# 扫雷板格类
class Cell:
def __init__(self, is_mine):
self.is_mine = is_mine
self.is_revealed = False
self.adjacent_mines = 0
# 创建游戏板
board = [[Cell(False) for _ in range(board_size)] for _ in range(board_size)]
***
相关问题
帮我写一个python扫雷游戏代码
当然可以帮您写一个简单的Python扫雷游戏代码。
首先,您需要安装Python。安装完成后,您可以在您的计算机上创建一个新文件,将其命名为“minesweeper.py”,然后将以下代码复制到文件中:
```
import random
# 设置游戏板的大小
board_size = 10
# 设置地雷的数量
num_bombs = 10
# 初始化游戏板
board = [[0 for i in range(board_size)] for j in range(board_size)]
# 初始化地雷
bombs = random.sample(range(board_size*board_size), num_bombs)
for bomb in bombs:
row = bomb // board_size
col = bomb % board_size
board[row][col] = "B"
# 计算每个方格周围的地雷数量
for i in range(board_size):
for j in range(board_size):
if board[i][j] != "B":
count = 0
if i > 0 and board[i-1][j] == "B":
count += 1
if i < board_size-1 and board[i+1][j] == "B":
count += 1
if j > 0 and board[i][j-1] == "B":
count += 1
if j < board_size-1 and board[i][j+1] == "B":
count += 1
if i > 0 and j > 0 and board[i-1][j-1] == "B":
count += 1
if i > 0 and j < board_size-1 and board[i-1][j+1] == "B":
count += 1
if i < board_size-1 and j > 0 and board[i+1][j-1] == "B":
count += 1
if i < board_size-1 and j < board_size-1 and board[i+1][j+1] == "B":
count += 1
board[i][j] = count
# 打印游戏板
for i in range(board_size):
for j in range(board_size):
print(board[i][j], end=" ")
print()
```
这个简单的代码会在游戏板上随机放置一些地雷,然后计算每个方格周围的地雷数量,并将其打印在游戏板上。您可以根据自己的需要添加其他功能,例如在游戏板上添加用户输入,并根据用户输入更新游戏板。
写一个Python扫雷代码
### 回答1:
好的,这是一个简单的Python扫雷代码的例子:
```
import random
class MineSweeper:
def __init__(self, size=10, mines=10):
self.size = size
self.mines = mines
self.board = [[0 for j in range(self.size)] for i in range(self.size)]
self.hidden_board = [['-' for j in range(self.size)] for i in range(self.size)]
self.generate_mines()
self.calculate_numbers()
def generate_mines(self):
mines_placed = 0
while mines_placed < self.mines:
i = random.randint(0, self.size - 1)
j = random.randint(0, self.size - 1)
if self.board[i][j] != '*':
self.board[i][j] = '*'
mines_placed += 1
def calculate_numbers(self):
for i in range(self.size):
for j in range(self.size):
if self.board[i][j] == '*':
continue
count = 0
for x in range(i-1, i+2):
for y in range(j-1, j+2):
if x >= 0 and x < self.size and y >= 0 and y < self.size and self.board[x][y] == '*':
count += 1
self.board[i][j] = count
def display(self):
for i in range(self.size):
for j in range(self.size):
print(self.hidden_board[i][j], end=' ')
print()
def play(self):
print("Let's play MineSweeper!")
while True:
self.display()
row = int(input("Enter row (0-{}): ".format(self.size - 1)))
col = int(input("Enter col (0-{}): ".format(self.size - 1)))
if self.board[row][col] == '*':
print("You stepped on a mine. Game over.")
break
self.hidden_board[row][col] = self.board[row][col]
print("Good choice!")
if __name__ == '__main__':
game = MineSweeper()
game.play()
```
这是一个简单的扫雷游戏代码,你可以根据自己的需要对代码进行修改。
### 回答2:
这是一个简单的Python扫雷代码:
```python
import random
def create_board(rows, columns, num_mines):
# 创建一个空白的游戏板
board = [[0] * columns for _ in range(rows)]
# 随机放置雷
mines = random.sample(range(rows * columns), num_mines)
for mine in mines:
row = mine // columns
col = mine % columns
board[row][col] = -1
# 计算周围雷的数量
for i in range(rows):
for j in range(columns):
if board[i][j] != -1:
count = 0
for x in range(max(0, i - 1), min(i + 1, rows - 1) + 1):
for y in range(max(0, j - 1), min(j + 1, columns - 1) + 1):
if board[x][y] == -1:
count += 1
board[i][j] = count
return board
def play_game(board):
rows = len(board)
columns = len(board[0])
uncovered = [[False] * columns for _ in range(rows)]
game_over = False
while not game_over:
print_board(board, uncovered)
row = int(input("请输入要揭开的行数:"))
col = int(input("请输入要揭开的列数:"))
if board[row][col] == -1:
game_over = True
print("踩到雷了,游戏结束!")
print_board(board, uncovered)
else:
uncovered[row][col] = True
if board[row][col] == 0:
uncover_empty_neighbors(board, uncovered, row, col)
if check_win(board, uncovered):
game_over = True
print("恭喜你,扫雷成功!")
print_board(board, uncovered)
def uncover_empty_neighbors(board, uncovered, row, col):
rows = len(board)
columns = len(board[0])
for x in range(max(0, row - 1), min(row + 1, rows - 1) + 1):
for y in range(max(0, col - 1), min(col + 1, columns - 1) + 1):
if not uncovered[x][y]:
uncovered[x][y] = True
if board[x][y] == 0:
uncover_empty_neighbors(board, uncovered, x, y)
def check_win(board, uncovered):
rows = len(board)
columns = len(board[0])
for i in range(rows):
for j in range(columns):
if board[i][j] != -1 and not uncovered[i][j]:
return False
return True
def print_board(board, uncovered):
rows = len(board)
columns = len(board[0])
for i in range(rows):
for j in range(columns):
if uncovered[i][j]:
print(board[i][j], end=" ")
else:
print("#", end=" ")
print()
# 游戏设置
rows = 10
columns = 10
num_mines = 10
# 创建游戏板
board = create_board(rows, columns, num_mines)
# 开始游戏
play_game(board)
```
以上代码实现了一个基本的扫雷游戏。首先通过`create_board()`函数创建一个雷区,并计算每个方块周围的雷的数量。然后通过`play_game()`函数进行游戏的主循环,玩家选择要揭开的方块并判断是否踩到雷。游戏板的显示和游戏结果的判断通过`print_board()`和`check_win()`函数完成。
阅读全文