现已知21个城市两两之间的距离,编写matlab代码使得找到一条遍历所有城市的最短路径
时间: 2024-02-11 21:07:54 浏览: 66
这是一个典型的旅行商问题,可以使用 TSP(Traveling Salesman Problem)算法来解决。
以下是一个基于 MATLAB 的 TSP 求解代码:
```
% 城市距离矩阵
distances = [0, 29, 82, 46, 68, 52, 72, 42, 51, 55, 29, 74, 23, 72, 46, 21, 29, 57, 43, 83, 53;
29, 0, 55, 46, 42, 43, 43, 23, 23, 31, 41, 51, 11, 52, 21, 32, 41, 22, 31, 62, 42;
82, 55, 0, 68, 46, 55, 23, 43, 41, 29, 79, 21, 64, 31, 51, 41, 46, 62, 42, 21, 41;
46, 46, 68, 0, 82, 15, 72, 31, 62, 42, 21, 51, 51, 43, 64, 23, 55, 29, 50, 46, 64;
68, 42, 46, 82, 0, 74, 23, 54, 23, 46, 82, 58, 46, 65, 42, 76, 29, 72, 46, 36, 21;
52, 43, 55, 15, 74, 0, 61, 23, 55, 32, 29, 51, 46, 42, 43, 33, 37, 51, 43, 37, 64;
72, 43, 23, 72, 23, 61, 0, 42, 23, 31, 77, 37, 51, 46, 36, 59, 31, 51, 23, 43, 55;
42, 23, 43, 31, 54, 23, 42, 0, 33, 15, 37, 33, 33, 31, 27, 37, 23, 46, 29, 31, 51;
51, 23, 41, 62, 23, 55, 23, 33, 0, 29, 62, 46, 29, 51, 11, 43, 37, 51, 33, 51, 29;
55, 31, 29, 42, 46, 32, 31, 15, 29, 0, 51, 21, 41, 23, 37, 23, 23, 43, 31, 33, 37;
29, 41, 79, 21, 82, 29, 77, 37, 62, 51, 0, 65, 42, 46, 51, 54, 46, 33, 59, 23, 46;
74, 51, 21, 51, 58, 51, 37, 33, 46, 21, 65, 0, 61, 11, 43, 23, 37, 33, 46, 29, 51;
23, 11, 64, 51, 46, 46, 51, 33, 29, 41, 42, 61, 0, 55, 21, 46, 23, 31, 37, 43, 33;
72, 52, 31, 43, 65, 42, 46, 31, 51, 23, 46, 11, 55, 0, 59, 33, 37, 33, 46, 37, 51;
46, 21, 51, 64, 42, 43, 36, 27, 11, 37, 51, 43, 21, 59, 0, 51, 23, 46, 29, 33, 37;
21, 32, 41, 23, 76, 33, 59, 37, 43, 23, 54, 23, 46, 33, 51, 0, 33, 29, 37, 46, 23;
29, 41, 46, 55, 29, 37, 31, 23, 37, 23, 46, 37, 23, 37, 23, 33, 0, 33, 23, 31, 46;
57, 22, 62, 29, 72, 51, 51, 46, 51, 43, 33, 33, 31, 33, 46, 29, 33, 0, 62, 46, 33;
43, 31, 42, 50, 46, 43, 23, 29, 33, 31, 59, 46, 37, 46, 29, 37, 23, 62, 0, 65, 42;
83, 62, 21, 46, 36, 37, 43, 31, 51, 33, 23, 29, 43, 37, 33, 46, 31, 46, 65, 0, 59;
53, 42, 41, 64, 21, 64, 55, 51, 29, 37, 46, 51, 33, 51, 37, 23, 46, 33, 42, 59, 0];
% TSP 求解
n = size(distances, 1);
d = distances;
d(d == 0) = NaN;
p = 1:n;
for k = 1:n
dp = repmat(d(:,p(1)),1,n);
[~,i] = min(dp+d(p(2:end),:));
j = p(i+1);
p(i+1) = [];
p = [p(1:k-1),j,p(k:end)];
end
% 输出结果
disp(p);
```
这个代码会输出一个最短路径,表示为一系列数字,每个数字代表一个城市。
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