用c语言编写程序求ax 2 +bx+c=0方程的根，其中a,b,c从键盘输入

#include <stdio.h>
#include <math.h>

int main() {
    float a, b, c, discriminant, root1, root2;

    printf("Enter coefficients a, b, c: ");
    scanf("%f %f %f", &a, &b, &c);

    discriminant = b * b - 4 * a * c;

    if (discriminant > 0) {
        root1 = (-b + sqrt(discriminant)) / (2 * a);
        root2 = (-b - sqrt(discriminant)) / (2 * a);
        printf("Roots are real and different.\n");
        printf("Root1 = %.2f and Root2 = %.2f", root1, root2);
    } else if (discriminant == 0) {
        root1 = root2 = -b / (2 * a);
        printf("Roots are real and same.\n");
        printf("Root1 = Root2 = %.2f", root1);
    } else {
        float realPart = -b / (2 * a);
        float imaginaryPart = sqrt(-discriminant) / (2 * a);
        printf("Roots are complex and different.\n");
        printf("Root1 = %.2f + %.2fi and Root2 = %.2f - %.2fi", realPart, imaginaryPart, realPart, imaginaryPart);
    }

    return 0;
}

注：%.2f表示保留两位小数输出。