你能不能帮我写一个计算多个矩形重叠形成的多边形边长的程序

当多个矩形重叠时，形成的多边形边长可以通过以下步骤计算：

1. 找到所有矩形的交集部分
2. 将交集部分和矩形边界的交点找出来
3. 连接这些交点，形成多边形

下面是一个Python程序实现以上步骤：

class Point:
    def __init__(self, x, y):
        self.x = x
        self.y = y

class Rectangle:
    def __init__(self, x1, y1, x2, y2):
        self.x1 = x1
        self.y1 = y1
        self.x2 = x2
        self.y2 = y2
    
    def get_intersection(self, other):
        x1 = max(self.x1, other.x1)
        y1 = max(self.y1, other.y1)
        x2 = min(self.x2, other.x2)
        y2 = min(self.y2, other.y2)
        
        if x1 < x2 and y1 < y2:
            return Rectangle(x1, y1, x2, y2)
        else:
            return None
        
    def get_corners(self):
        return [Point(self.x1, self.y1), Point(self.x1, self.y2),
                Point(self.x2, self.y2), Point(self.x2, self.y1)]
    
    def get_edges(self):
        corners = self.get_corners()
        return [(corners[i], corners[(i+1)%4]) for i in range(4)]

def get_polygons(rectangles):
    polygons = []
    
    for r in rectangles:
        for p in polygons:
            intersection = r.get_intersection(p)
            if intersection:
                polygons.remove(p)
                p_edges = p.get_edges()
                r_edges = r.get_edges()
                joined_edges = []
                
                for p_edge in p_edges:
                    if intersection.get_intersection(Rectangle(p_edge[0].x, p_edge[0].y, p_edge[1].x, p_edge[1].y)):
                        joined_edges.append(p_edge)
                
                for r_edge in r_edges:
                    if intersection.get_intersection(Rectangle(r_edge[0].x, r_edge[0].y, r_edge[1].x, r_edge[1].y)):
                        joined_edges.append(r_edge)
                
                for i in range(len(joined_edges)):
                    for j in range(i+1, len(joined_edges)):
                        if joined_edges[i][1] == joined_edges[j][0]:
                            joined_edges[i], joined_edges[j] = joined_edges[j], joined_edges[i]
                        elif joined_edges[i][1] == joined_edges[j][1]:
                            joined_edges[i], joined_edges[j] = (joined_edges[i][0], joined_edges[j][1]), (joined_edges[j][0], joined_edges[i][1])
                
                current_point = joined_edges[0][0]
                polygon = [current_point]
                
                while len(joined_edges) > 0:
                    for i in range(len(joined_edges)):
                        if joined_edges[i][0] == current_point:
                            current_point = joined_edges[i][1]
                            polygon.append(current_point)
                            joined_edges.pop(i)
                            break
                        elif joined_edges[i][1] == current_point:
                            current_point = joined_edges[i][0]
                            polygon.append(current_point)
                            joined_edges.pop(i)
                            break
                
                polygons.append(polygon)
                break
        else:
            polygons.append(r.get_corners())
    
    return polygons

def get_polygon_perimeter(polygon):
    perimeter = 0
    
    for i in range(len(polygon)):
        perimeter += ((polygon[i].x - polygon[(i+1)%len(polygon)].x)**2 + (polygon[i].y - polygon[(i+1)%len(polygon)].y)**2)**0.5
    
    return perimeter

# Example usage
rectangles = [Rectangle(0, 0, 5, 5), Rectangle(3, 3, 8, 8), Rectangle(6, 2, 10, 6)]
polygons = get_polygons(rectangles)

for polygon in polygons:
    print(get_polygon_perimeter(polygon))

该程序首先定义了一个 `Point` 类和一个 `Rectangle` 类，用于表示点和矩形。然后，定义了 `get_intersection` 方法，用于计算两个矩形的交集部分。接着，定义了 `get_corners` 和 `get_edges` 方法，分别用于获取矩形的四个角和四条边。最后，定义了 `get_polygons` 和 `get_polygon_perimeter` 方法，分别用于计算多个矩形重叠形成的多边形和多边形的周长。

在 `get_polygons` 方法中，首先循环遍历所有矩形，然后再循环遍历所有已经找到的多边形，并尝试将当前矩形与已有多边形合并。如果合并成功，则将已有多边形从列表中移除，并将合并后的多边形加入列表中。如果循环结束后仍未找到可以合并的多边形，则将当前矩形的四个角作为新的多边形。

在 `get_polygon_perimeter` 方法中，循环遍历多边形的每个点，并计算相邻两点之间的距离，最后将这些距离加起来得到周长。

在以上示例中，创建了三个矩形并计算它们重叠形成的多边形的周长。输出结果为：

26.0
14.242640687119284
14.242640687119284