c语言Give+two+integers+n+and+m，you+should+compute+the+sum+of+all+the+integers+form+n+to+m.In+other+woo

给定两个整数n和m，计算从n到m的所有整数的总和。可以使用循环结构来实现这个功能，例如for循环或while循环。具体实现方法如下所示：

#include <stdio.h>

int main() {
    int n, m, sum = 0;
    scanf("%d %d", &n, &m);
    for (int i = n; i <= m; i++) {
        sum += i;
    }
    printf("Sum of integers from %d to %d is %d\n", n, m, sum);
    return 0;
}

相关问题

Your+task+is+to+Calculate+the+sum+of+some+integers

Sure! To calculate the sum of some integers, you can follow these steps:

1. Define a variable to store the sum, let's call it "total", and initialize it to 0.
2. Iterate through the integers you want to sum.
3. For each integer, add it to the "total" variable.
4. After iterating through all the integers, the final value of "total" will be the sum of the integers.

Here's an example in Python:

# Define the integers
integers = [1, 2, 3, 4, 5]

# Calculate the sum
total = 0
for num in integers:
    total += num

# Print the result
print("The sum is:", total)

In this example, the sum of the integers [1, 2, 3, 4, 5] is calculated and stored in the "total" variable. The result is then printed as "The sum is: 15".

Write+a+program+to+find+all+the+integers+whose+sum+of+three+digits+is+10+between+100+and+num+(not+mo

以下是Python程序，用于查找所有三位数中数字之和为10的整数：

result = []
for i in range(100, num+1):
    if sum(int(digit) for digit in str(i)) == 10:
        result.append(i)
print(result)

该程序使用for循环遍历从100到num的所有整数。对于每个整数，它将其转换为字符串并将其拆分为单个数字。然后，它将这些数字转换回整数并将它们相加以计算数字之和。如果数字之和等于10，则将该整数添加到结果列表中。最后，程序打印结果列表。