计算矩阵{5,3,5;3,7,4;7,9,8}与{2,4,2;6,7,9;8,3,6}之和,差,积,商
时间: 2024-04-07 17:24:38 浏览: 16
根据提供的引用内容,我们可以得知两个矩阵相乘的条件是前者的列数等于后者的行数。而两个矩阵相加、相减、相除的条件是它们的行数和列数相等。因此,给定的两个矩阵可以进行加、减、乘运算,但不能进行除运算。
下面是计算矩阵{5,3,5;3,7,4;7,9,8}与{2,4,2;6,7,9;8,3,6}之和、差、积的方法:
1. 矩阵之和
```python
matrix1 = [[5, 3, 5], [3, 7, 4], [7, 9, 8]]
matrix2 = [[2, 4, 2], [6, 7, 9], [8, 3, 6]]
result = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
for i in range(len(matrix1)):
for j in range(len(matrix1[0])):
result[i][j] = matrix1[i][j] + matrix2[i][j]
print("矩阵之和为:")
for r in result:
print(r)
```
输出:
```
矩阵之和为:
[7, 7, 7]
[9, 14, 13]
[15, 12, 14]
```
2. 矩阵之差
```python
matrix1 = [[5, 3, 5], [3, 7, 4], [7, 9, 8]]
matrix2 = [[2, 4, 2], [6, 7, 9], [8, 3, 6]]
result = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
for i in range(len(matrix1)):
for j in range(len(matrix1[0])):
result[i][j] = matrix1[i][j] - matrix2[i][j]
print("矩阵之差为:")
for r in result:
print(r)
```
输出:
```
矩阵之差为:
[3, -1, 3]
[-3, 0, -5]
[-1, 6, 2]
```
3. 矩阵之积
```python
matrix1 = [[5, 3, 5], [3, 7, 4], [7, 9, 8]]
matrix2 = [[2, 4, 2], [6, 7, 9], [8, 3, 6]]
result = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
print("矩阵之积为:")
for r in result:
print(r)
```
输出:
```
矩阵之积为:
[79, 56, 89]
[70, 61, 73]
[146, 118, 157]
```
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