实现8个绿灯LEDG0~LEDG7、16个红灯LEDR0~LEDR15流动顺序点亮。
时间: 2023-07-18 21:03:46 浏览: 204
以下是使用Verilog HDL实现该功能的代码:
```verilog
module LED_Controller(
input clk,
output reg [7:0] LED_Green,
output reg [15:0] LED_Red
);
reg [3:0] counter;
always @(posedge clk) begin
if (counter == 4'd15) begin
counter <= 4'd0;
end
else begin
counter <= counter + 1;
end
end
always @(posedge clk) begin
case (counter)
4'd0: begin
LED_Green <= 8'b00000001;
LED_Red <= 16'b0000000000000001;
end
4'd1: begin
LED_Green <= 8'b00000010;
LED_Red <= 16'b0000000000000010;
end
4'd2: begin
LED_Green <= 8'b00000100;
LED_Red <= 16'b0000000000000100;
end
4'd3: begin
LED_Green <= 8'b00001000;
LED_Red <= 16'b0000000000001000;
end
4'd4: begin
LED_Green <= 8'b00010000;
LED_Red <= 16'b0000000000010000;
end
4'd5: begin
LED_Green <= 8'b00100000;
LED_Red <= 16'b0000000000100000;
end
4'd6: begin
LED_Green <= 8'b01000000;
LED_Red <= 16'b0000000001000000;
end
4'd7: begin
LED_Green <= 8'b10000000;
LED_Red <= 16'b0000000010000000;
end
4'd8: begin
LED_Green <= 8'b01000000;
LED_Red <= 16'b0000000100000000;
end
4'd9: begin
LED_Green <= 8'b00100000;
LED_Red <= 16'b0000001000000000;
end
4'd10: begin
LED_Green <= 8'b00010000;
LED_Red <= 16'b0000010000000000;
end
4'd11: begin
LED_Green <= 8'b00001000;
LED_Red <= 16'b0000100000000000;
end
4'd12: begin
LED_Green <= 8'b00000100;
LED_Red <= 16'b0001000000000000;
end
4'd13: begin
LED_Green <= 8'b00000010;
LED_Red <= 16'b0010000000000000;
end
4'd14: begin
LED_Green <= 8'b00000001;
LED_Red <= 16'b0100000000000000;
end
4'd15: begin
LED_Green <= 8'b00000000;
LED_Red <= 16'b1000000000000000;
end
endcase
end
endmodule
```
在该代码中,我们使用了两个always块。第一个always块用于计数器的计数,它会在每个时钟上升沿时加1。当计数器达到最大值时,它会被重置为0。
第二个always块使用case语句根据计数器的值来选择点亮哪些LED。在每个时钟上升沿时,它将根据计数器的值设置LED_Green和LED_Red的值。
请注意,我们在代码中使用了二进制字面量,例如8'b00000001表示一个8位二进制数,其中只有最低位为1,其他位为0。类似地,16'b0000000000000001表示一个16位二进制数,其中只有最低位为1,其他位为0。
对于该代码的测试,我们可以使用FPGA板或仿真器。在仿真器中,我们可以将时钟信号作为输入,同时观察LED_Green和LED_Red的输出是否按照预期顺序点亮。
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