实现8个绿灯LEDG0~LEDG7、16个红灯LEDR0~LEDR15流动顺序点亮。流动点亮的起点为 LEDG0、LEDR0、和LEDR8，流动方向为从右往左。

这个任务可以通过FPGA来实现。以下是VHDL代码实现：

library ieee;
use ieee.std_logic_1164.all;

entity Traffic_Lights is
port (
    clk : in std_logic;
    reset : in std_logic;
    LEDG : out std_logic_vector(7 downto 0);
    LEDR : out std_logic_vector(15 downto 0)
);
end Traffic_Lights;

architecture Behavioral of Traffic_Lights is
signal counter : integer range 0 to 15 := 0;
signal direction : std_logic := '1'; --'1'表示从右往左，'0'表示从左往右
begin

process (clk, reset)
begin
    if reset = '1' then
        counter <= 0;
        direction <= '1';
        LEDG <= (others => '0');
        LEDR <= (others => '0');
    elsif rising_edge(clk) then
        if counter = 0 then
            LEDG <= "10000000";
            LEDR <= "0000000000000001";
        elsif counter = 1 then
            LEDG <= "11000000";
            LEDR <= "0000000000000011";
        elsif counter = 2 then
            LEDG <= "11100000";
            LEDR <= "0000000000000110";
        elsif counter = 3 then
            LEDG <= "11110000";
            LEDR <= "0000000000001100";
        elsif counter = 4 then
            LEDG <= "11111000";
            LEDR <= "0000000000011000";
        elsif counter = 5 then
            LEDG <= "11111100";
            LEDR <= "0000000000110000";
        elsif counter = 6 then
            LEDG <= "11111110";
            LEDR <= "0000000001100000";
        elsif counter = 7 then
            LEDG <= "11111111";
            LEDR <= "0000000011000000";
        elsif counter = 8 then
            LEDG <= "01111111";
            LEDR <= "0000000110000000";
        elsif counter = 9 then
            LEDG <= "00111111";
            LEDR <= "0000001100000000";
        elsif counter = 10 then
            LEDG <= "00011111";
            LEDR <= "0000011000000000";
        elsif counter = 11 then
            LEDG <= "00001111";
            LEDR <= "0000110000000000";
        elsif counter = 12 then
            LEDG <= "00000111";
            LEDR <= "0001100000000000";
        elsif counter = 13 then
            LEDG <= "00000011";
            LEDR <= "0011000000000000";
        elsif counter = 14 then
            LEDG <= "00000001";
            LEDR <= "0110000000000000";
        elsif counter = 15 then
            LEDG <= "00000000";
            LEDR <= "1100000000000000";
        end if;

        if direction = '1' then
            counter <= counter + 1;
            if counter = 15 then
                direction <= '0';
            end if;
        else
            counter <= counter - 1;
            if counter = 0 then
                direction <= '1';
            end if;
        end if;
    end if;
end process;

end Behavioral;

在这段代码中，对于每个计数器值，我们将对应的LED设置为1，其他的LED都设置为0。在每个时钟上升沿，计数器将增加或减少，取决于LED是否向左或向右移动。当计数器等于15时，方向将更改为向左，当计数器等于0时，方向将更改为向右。当复位信号为1时，所有LED都将关闭并重置计数器和方向。

请注意，此代码仅是实现的一种方法，可能有其他方法可以实现相同的功能。