请写一段用openmv和Dstar算法对数组迷宫进行路径规划1为墙壁,0为道路,2为起点与重点要求输出的路径用3表示数组如下Mi[21][21] = {(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1), (1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,2,1), (1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1), (1,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1), (1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,1,1,0,1), (1,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1), (1,1,1,0,1,0,1,0,1,1,1,1,1,0,1,1,1,0,1,1,1), (1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1), (1,0,1,1,1,0,1,0,1,1,1,1,1,1,1,0,1,1,1,0,1), (1,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1), (1,0,1,1,1,1,1,0,1,1,1,1,1,0,1,1,1,1,1,0,1), (1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,1), (1,0,1,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,1,0,1), (1,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1), (1,1,1,0,1,1,1,0,1,1,1,1,1,0,1,0,1,0,1,1,1), (1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,1), (1,0,1,1,1,0,1,0,1,1,1,0,1,1,1,0,1,1,1,0,1), (1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,1), (1,1,1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1), (1,2,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1), (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1)}
时间: 2023-09-30 21:06:12 浏览: 38
请注意,由于我是一个文本AI模型,我无法直接操作OpenMV或编写代码。然而,我可以为您提供一个基于OpenMV和D*算法的路径规划示例代码,您可以将其运行在OpenMV上。
```python
# 导入所需库
import sensor
import image
import time
# 定义迷宫数组
maze = [[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1],
[1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,2,1],
[1,0,1,0,1,1,1,0,1,0,1,0,1,1,1,0,1,0,1,1,1],
[1,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,1],
[1,0,1,1,1,0,1,1,1,0,1,1,1,0,1,0,1,
# 初始化OpenMV摄像头
sensor.reset()
sensor.set_pixformat(sensor.RGB565)
sensor.set_framesize(sensor.QVGA)
sensor.skip_frames(time = 200)
# 定义迷宫的宽度和高度
maze_width = len(maze[0])
maze_height = len(maze)
# 定义起点和终点的坐标
start = (0, 1)
end = (maze_height - 1, maze_width - 2)
# 定义D*算法的节点类
class Node:
def __init__(self, x, y):
self.x = x
self.y = y
self.g = float("inf")
self.rhs = float("inf")
self.parent = None
def __lt__(self, other):
return (self.g + self.h) < (other.g + other.h)
# 定义D*算法的路径规划函数
def DStar(maze, start, end):
# 初始化节点列表
nodes = [[Node(i, j) for j in range(maze_width)] for i in range(maze_height)]
# 设置起点和终点的代价值
nodes[start[0]][start[1]].g = 0
nodes[start[0]][start[1]].rhs = 0
# 定义启发式函数(欧几里得距离)
def heuristic(node):
return ((node.x - end[0]) ** 2 + (node.y - end[1]) ** 2) ** 0.5
# 更新节点的代价值
def updateNode(node):
if node != start:
g_values = [nodes[node.x-1][node.y].g + 1,
nodes[node.x+1][node.y].g + 1,
nodes[node.x][node.y-1].g + 1,
nodes[node.x][node.y+1].g + 1]
node.rhs = min(g_values)
if node in open_list:
open_list.remove(node)
if node.g != node.rhs:
open_list.append(node)
# 更新节点的父节点
def updateParent(node):
min_g = float("inf")
parent = None
neighbors = [(node.x-1, node.y),
(node.x+1, node.y),
(node.x, node.y-1),
(node.x, node.y+1)]
for neighbor in neighbors:
if 0 <= neighbor[0] < maze_height and 0 <= neighbor[1] < maze_width:
if nodes[neighbor[0]][neighbor[1]].g + 1 < min_g:
min_g = nodes[neighbor[0]][neighbor[1]].g + 1
parent = (neighbor[0], neighbor[1])
node.g = min_g
node.parent = parent
# 初始化开放列表和关闭列表
open_list = [nodes[end[0]][end[1]]]
closed_list = []
# 开始路径规划
while open_list:
current = min(open_list)
if current == nodes[start[0]][start[1]]:
break
open_list.remove(current)
closed_list.append(current)
neighbors = [(current.x-1, current.y),
(current.x+1, current.y),
(current.x, current.y-1),
(current.x, current.y+1)]
for neighbor in neighbors:
if 0 <= neighbor[0] < maze_height and 0 <= neighbor[1] < maze_width:
if maze[neighbor[0]][neighbor[1]] == 1:
continue
if nodes[neighbor[0]][neighbor[1]] not in closed_list:
updateParent(nodes[neighbor[0]][neighbor[1]])
if nodes[neighbor[0]][neighbor[1]] not in open_list:
open_list.append(nodes[neighbor[0]][neighbor[1]])
updateNode(nodes[neighbor[0]][neighbor[1]])
# 输出路径
path = []
current = nodes[start[0]][start[1]]
while current != nodes[end[0]][end[1]]:
path.append((current.x, current.y))
current = nodes[current.parent[0]][current.parent[1]]
path.append(end)
return path
# 进行路径规划
path = DStar(maze, start, end)
print(path)
```
请将以上代码复制到OpenMV IDE中,并根据您的具体需求进行修改和调试。运行代码后,您将获得一条路径,路径上的坐标用于找到在迷宫数组中对应的位置,并将其值设置为3以表示路径。
请注意,以上代码仅是一个示例,可能需要根据实际情况进行调整和优化。希望对您有所帮助!如有任何问题,请随时向我提问。