复杂的贪吃蛇游戏python代码
时间: 2024-07-18 14:01:27 浏览: 61
创建一个复杂的贪吃蛇游戏的Python代码需要考虑几个关键部分:游戏界面、蛇的行为、食物生成、碰撞检测等。这里是一个简化版的基本框架示例:
```python
import pygame
import random
# 初始化pygame
pygame.init()
# 设置窗口大小
window_size = (800, 600)
screen = pygame.display.set_mode(window_size)
pygame.display.set_caption("贪吃蛇")
snake_speed = 5
snake_body = [(100, 100), (90, 100), (80, 100)] # 起始蛇的身体
direction = 'right' # 蛇的初始方向
# 食物位置
food_pos = (random.randint(0, window_size - 20), random.randint(0, window_size - 20))
food_color = (0, 255, 0) # 食物颜色
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
keys = pygame.key.get_pressed()
if keys[pygame.K_UP] and direction != 'down':
direction = 'up'
elif keys[pygame.K_DOWN] and direction != 'up':
direction = 'down'
elif keys[pygame.K_LEFT] and direction != 'right':
direction = 'left'
elif keys[pygame.K_RIGHT] and direction != 'left':
direction = 'right'
# 更新蛇的位置
new_head = snake_body
if direction == 'up':
new_head = (new_head, new_head - snake_speed)
elif direction == 'down':
new_head = (new_head, new_head + snake_speed)
elif direction == 'left':
new_head = (new_head - snake_speed, new_head)
else: # right
new_head = (new_head + snake_speed, new_head)
snake_body.insert(0, new_head)
# 检查蛇是否吃到食物
if snake_body == food_pos:
food_pos = (random.randint(0, window_size - 20), random.randint(0, window_size - 20))
snake_length += 1
else:
snake_body.pop()
# 碰撞检测
if snake_body in snake_body[1:]:
pygame.quit()
quit()
screen.fill((255, 255, 255)) # 清空屏幕
for pos in snake_body:
pygame.draw.rect(screen, (0,
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