在一个迷宫中，必须从1个起点进入，然后走过指定的4个点，然后从给的3个终点里面选择一个出去，这个迷宫可以重复走，但是要保证这些重复是有价值的，而不是多余，这种情况下，怎么设计一个算法选择最快的走法，用matlab怎么么实现？能不能给我一个实现的代码？

这是一个比较复杂的问题，需要先设计一个合适的算法，然后再用MATLAB实现。以下是一种可能的算法：

1. 使用广度优先搜索算法，从起点开始搜索，记录每个节点的状态（已经经过还是未经过）和到达该节点的路径长度。
2. 当搜索到指定的4个点时，记录此时的状态和路径长度，并继续搜索直到搜索到3个终点为止。
3. 对于每个搜索到的状态，记录到达该状态的路径长度和从该状态出发到达终点的路径长度之和。
4. 在搜索结束后，选择路径长度最短的状态，并输出从起点到该状态的路径和从该状态到终点的路径。

以下是MATLAB的实现代码：

% 迷宫地图
map = [0 0 0 1 1 0 1 0;
       0 1 0 0 0 0 0 0;
       0 1 1 0 1 0 1 0;
       0 0 1 0 0 1 0 0;
       1 0 0 1 0 0 0 0;
       0 0 1 1 0 1 1 0;
       1 0 0 0 0 0 0 0;
       0 0 1 0 1 1 0 0];

% 起点、终点和指定的4个点
start = [1, 1];
endpoints = {[1, 8], [4, 1], [8, 2]};
checkpoints = {[2, 5], [3, 2], [5, 1], [7, 1]};

% 记录已经访问的节点
visited = zeros(size(map));

% 记录每个节点的状态和路径长度
state = cell(size(map));
distance = cell(size(map));
for i = 1:size(map, 1)
    for j = 1:size(map, 2)
        state{i, j} = 'unvisited';
        distance{i, j} = Inf;
    end
end

% 广度优先搜索
queue = [start, 0];
while ~isempty(queue)
    % 出队
    curr = queue(1:2);
    dist = queue(3);
    queue(1:3) = [];
    
    % 判断是否到达指定的4个点
    if ismember(curr, checkpoints, 'rows')
        checkpointIndex = find(ismember(checkpoints, curr, 'rows'));
        state{curr(1), curr(2)} = strcat('checkpoint', num2str(checkpointIndex));
        distance{curr(1), curr(2)} = dist;
    end
    
    % 判断是否到达终点
    if ismember(curr, endpoints, 'rows')
        endIndex = find(ismember(endpoints, curr, 'rows'));
        state{curr(1), curr(2)} = strcat('end', num2str(endIndex));
        distance{curr(1), curr(2)} = dist;
    end
    
    % 标记已经访问的节点
    visited(curr(1), curr(2)) = 1;
    
    % 扩展节点
    neighbors = getNeighbors(curr, map);
    for i = 1:size(neighbors, 1)
        neighbor = neighbors(i, :);
        if visited(neighbor(1), neighbor(2)) == 0
            queue(end+1, :) = [neighbor, dist+1];
            state{neighbor(1), neighbor(2)} = strcat('visited', num2str(i));
            distance{neighbor(1), neighbor(2)} = dist + 1;
        end
    end
end

% 计算每个状态的路径长度和从该状态到终点的路径长度之和
totalDistance = cell(size(map));
for i = 1:size(map, 1)
    for j = 1:size(map, 2)
        if strcmp(state{i, j}, 'unvisited')
            totalDistance{i, j} = Inf;
        elseif strcmp(state{i, j}(1:9), 'checkpoint')
            checkpointIndex = str2double(state{i, j}(10:end));
            endDistances = cellfun(@(x) distance{x(1), x(2)}, endpoints);
            totalDistance{i, j} = distance{i, j} + min(endDistances);
        elseif strcmp(state{i, j}(1:3), 'end')
            endIndex = str2double(state{i, j}(4:end));
            totalDistance{i, j} = distance{i, j};
        end
    end
end

% 找到路径长度最短的状态
minTotalDistance = Inf;
minState = [0, 0];
for i = 1:size(map, 1)
    for j = 1:size(map, 2)
        if totalDistance{i, j} < minTotalDistance
            minTotalDistance = totalDistance{i, j};
            minState = [i, j];
        end
    end
end

% 输出路径
path = getPath(start, minState, state);
endIndex = str2double(state{minState(1), minState(2)}(4:end));
endPoint = endpoints{endIndex};
path = [path; endPoint];
disp(path);

其中，`getNeighbors`函数用于获取当前节点的邻居节点：

function neighbors = getNeighbors(curr, map)
% 获取当前节点的邻居节点
neighbors = [];
if curr(1) > 1 && map(curr(1)-1, curr(2)) == 0
    neighbors(end+1, :) = [curr(1)-1, curr(2)];
end
if curr(1) < size(map, 1) && map(curr(1)+1, curr(2)) == 0
    neighbors(end+1, :) = [curr(1)+1, curr(2)];
end
if curr(2) > 1 && map(curr(1), curr(2)-1) == 0
    neighbors(end+1, :) = [curr(1), curr(2)-1];
end
if curr(2) < size(map, 2) && map(curr(1), curr(2)+1) == 0
    neighbors(end+1, :) = [curr(1), curr(2)+1];
end
end

`getPath`函数用于获取从起点到终点的路径：

function path = getPath(start, endState, state)
% 获取从起点到终点的路径
path = [];
curr = endState;
while ~isequal(curr, start)
    path = [curr; path];
    if strcmp(state{curr(1), curr(2)}(1:8), 'visited')
        visitedIndex = str2double(state{curr(1), curr(2)}(9:end));
        neighbors = getNeighbors(curr, ones(size(state)));
        prev = neighbors(visitedIndex, :);
    elseif strcmp(state{curr(1), curr(2)}(1:9), 'checkpoint')
        checkpointIndex = str2double(state{curr(1), curr(2)}(10:end));
        endDistances = cellfun(@(x) state{x(1), x(2)}, state(curr(1), curr(2)));
        minEndIndex = find(strcmp(endDistances, strcat('end', num2str(checkpointIndex))));
        prev = cell2mat(endpoints(minEndIndex));
    end
    curr = prev;
end
path = [start; path];
end

需要注意的是，这只是一种可能的算法和实现方式，可能还有其他更好的算法和实现方式。