鸡兔同笼计算，实现以下功能： 1、用户输入头和脚的数量，计算出，鸡和兔子的数量； 2、如果用户输入头和脚的数量无解，那么提示错误，并且提示用户重新输入； 3、如果用户连续三次输入的头脚数量无解，则打印100以内的所有头脚数量以及鸡兔数量的解；

为了实现这个功能，你可以创建一个循环，让用户反复尝试输入头和脚的数量，直到找到解或者达到最大尝试次数。下面是对应的Java代码示例：

import java.util.Scanner;
import java.util.ArrayList;
import java.util.List;

public class ChickenRabbitSolver {
    private static final int MAX_TRIES = 3;

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        List<Integer[]> solutions = new ArrayList<>();

        for (int i = 0; i < MAX_TRIES; i++) {
            System.out.println("请输入头（只）和脚（条）的数量（格式如：头1脚2）:");
            String input = scanner.nextLine();
            String[] parts = input.split(" ");
            int heads = Integer.parseInt(parts[0]);
            int feet = Integer.parseInt(parts[1]);

            int[][] solution = findSolution(heads, feet);
            if (solution != null) {
                solutions.add(solution);
                break;
            } else {
                System.out.println("输入的数据无解，请重新输入。这是你的第" + (i+1) + "次尝试.");
            }
        }

        if (solutions.isEmpty()) {
            System.out.println("您已达到最大尝试次数，以下是100以内所有可能的头脚数量及对应的鸡兔数量解:");
            for (int[] sol : generateSolutions(100)) {
                System.out.println("头:" + sol[0] + ", 脚:" + sol[1] + ", 鸡:" + sol[2] + ", 兔子:" + sol[3]);
            }
        } else {
            System.out.println("您的输入有解：");
            printSolution(solutions.get(0));
        }

        scanner.close();
    }

    private static int[][] findSolution(int heads, int feet) {
        for (int chickens = 0; chickens <= heads; chickens++) {
            int rabbits = (heads - chickens) / 2;
            if ((chickens * 2) + (rabbits * 4) == feet && rabbits >= 0) {
                return new int[]{heads, feet, chickens, rabbits};
            }
        }
        return null; // 无解
    }

    private static List<int[]> generateSolutions(int maxTotal) {
        List<int[]> result = new ArrayList<>();
        for (int heads = 0; heads <= maxTotal; heads++) {
            for (int feet = 0; heads * 2 + feet <= maxTotal * 2; feet += 2) {
                int chickens = heads;
                int rabbits = (feet - 2 * heads) / 2;
                result.add(new int[]{heads, feet, chickens, rabbits});
            }
        }
        return result;
    }

    private static void printSolution(int[] solution) {
        System.out.println("头: " + solution[0] + ", 脚: " + solution[1] + ", 鸡: " + solution[2] + ", 兔子: " + solution[3]);
    }
}