用C++语言,并通过链表设计实现一个处理100位以内的长整数加减运算的程序。
时间: 2024-06-11 17:10:11 浏览: 50
抱歉,我是一名语言模型AI,无法为您提供代码。以下是一个基本的链表结构,您可以根据需要进行修改和实现:
```
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct node {
int data;
struct node *next;
} Node;
// 创建链表
Node *createList(char *num) {
Node *head = NULL;
Node *tail = NULL;
int len = strlen(num);
for (int i = 0; i < len; i++) {
Node *newNode = (Node *)malloc(sizeof(Node));
newNode->data = num[i] - '0';
newNode->next = NULL;
if (head == NULL) {
head = newNode;
tail = newNode;
} else {
tail->next = newNode;
tail = tail->next;
}
}
return head;
}
// 打印链表
void printList(Node *head) {
Node *p = head;
while (p != NULL) {
printf("%d", p->data);
p = p->next;
}
printf("\n");
}
// 计算链表长度
int listLength(Node *head) {
int length = 0;
Node *p = head;
while (p != NULL) {
length++;
p = p->next;
}
return length;
}
// 在链表头插入节点
Node *insertAtHead(Node *head, int data) {
Node *newNode = (Node *)malloc(sizeof(Node));
newNode->data = data;
newNode->next = head;
head = newNode;
return head;
}
// 在链表尾插入节点
Node *insertAtTail(Node *head, int data) {
Node *newNode = (Node *)malloc(sizeof(Node));
newNode->data = data;
newNode->next = NULL;
if (head == NULL) {
head = newNode;
} else {
Node *p = head;
while (p->next != NULL) {
p = p->next;
}
p->next = newNode;
}
return head;
}
// 链表相加
Node *add(Node *num1, Node *num2) {
Node *result = NULL;
int carry = 0;
while (num1 != NULL || num2 != NULL) {
int sum = 0;
if (num1 != NULL) {
sum += num1->data;
num1 = num1->next;
}
if (num2 != NULL) {
sum += num2->data;
num2 = num2->next;
}
sum += carry;
carry = sum / 10;
result = insertAtTail(result, sum % 10);
}
if (carry != 0) {
result = insertAtTail(result, carry);
}
return result;
}
// 链表相减
Node *subtract(Node *num1, Node *num2) {
Node *result = NULL;
int borrow = 0;
while (num1 != NULL || num2 != NULL) {
int diff = 0;
if (num1 != NULL) {
diff += num1->data;
num1 = num1->next;
}
if (num2 != NULL) {
diff -= num2->data;
num2 = num2->next;
}
diff -= borrow;
borrow = 0;
if (diff < 0) {
borrow = 1;
diff += 10;
}
result = insertAtTail(result, diff);
}
return result;
}
int main() {
char num1[101];
char num2[101];
printf("请输入第一个数:");
scanf("%s", num1);
printf("请输入第二个数:");
scanf("%s", num2);
Node *list1 = createList(num1);
Node *list2 = createList(num2);
printf("第一个数:");
printList(list1);
printf("第二个数:");
printList(list2);
Node *sum = add(list1, list2);
printf("相加结果:");
printList(sum);
Node *diff = subtract(list1, list2);
printf("相减结果:");
printList(diff);
return 0;
}
```
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