4'd6:begin count_r1=count<<2; count_r2=count_r1+count; // if(count<64) begin if(count[7:6]==0) begin raddr_data1<=count_r1; raddr_data2<=(count_r1)+1; raddr_data3<=(count_r1)+2; raddr_data4<=(count_r1)+3; raddr_w1<=(count_r2)+105; raddr_w2<=(count_r2)+106; raddr_w3<=(count_r2)+107; raddr_w4<=(count_r2)+108; raddr_w5<=(count_r2)+109; end else begin raddr_data1<=0; raddr_data2<=0; raddr_data3<=0; raddr_data4<=0; raddr_w1<=0; raddr_w2<=0; raddr_w3<=0; raddr_w4<=0; raddr_w5<=0; end end 怎么优化这段代码来减少硬件资源消耗
时间: 2024-02-10 08:11:49 浏览: 22
这段代码中的硬件资源消耗主要集中在了分支语句上,因此可以考虑使用条件运算符代替分支语句实现功能。改写后的代码如下:
```
raddr_data1 <= count[7:6] == 0 ? count << 2 : 0;
raddr_data2 <= count[7:6] == 0 ? (count << 2) + 1 : 0;
raddr_data3 <= count[7:6] == 0 ? (count << 2) + 2 : 0;
raddr_data4 <= count[7:6] == 0 ? (count << 2) + 3 : 0;
raddr_w1 <= count[7:6] == 0 ? (count << 2) + count + 105 : 0;
raddr_w2 <= count[7:6] == 0 ? (count << 2) + count + 106 : 0;
raddr_w3 <= count[7:6] == 0 ? (count << 2) + count + 107 : 0;
raddr_w4 <= count[7:6] == 0 ? (count << 2) + count + 108 : 0;
raddr_w5 <= count[7:6] == 0 ? (count << 2) + count + 109 : 0;
```
这里使用了条件运算符,如果 `count[7:6]` 为 0,则执行对应的操作,否则赋值为 0。这样可以消除分支语句的消耗,从而减少硬件资源的消耗。
相关问题
module race_game ( input clk , input rst , input [3:0]key , output [6:0]seg_led_1 , output [6:0]seg_led_2 , ); reg clk_divided; reg [6:0] seg[9:0]; reg [23:0] cnt; integer k; localparam PERIOD = 12000000; // 12MHz时钟信号的周期数 always @(posedge clk) begin if (!rst) begin cnt <= 0; clk_divided <= 0; end else begin if (cnt >= PERIOD-1) begin cnt <= 0; clk_divided <= ~clk_divided; end else begin cnt <= cnt + 1; end end end initial begin seg[0] = 7'h3f; // 0 seg[1] = 7'h06; // 1 seg[2] = 7'h5b; // 2 seg[3] = 7'h4f; // 3 seg[4] = 7'h66; // 4 seg[5] = 7'h6d; // 5 seg[6] = 7'h7d; // 6 seg[7] = 7'h07; // 7 seg[8] = 7'h7f; // 8 seg[9] = 7'h6f; // 9 end always @ (posedge clk_divided) begin if(!rst) begin for(k=10;k>0;k=k-1) begin case(k) 1'd0:begin seg_led_1<=seg[0];seg_led_2<=seg[0]; end 1'd1:begin seg_led_1<=seg[0];seg_led_2<=seg[1]; end 1'd2:begin seg_led_1<=seg[0];seg_led_2<=seg[2]; end 1'd3:begin seg_led_1<=seg[0];seg_led_2<=seg[3]; end 1'd4:begin seg_led_1<=seg[0];seg_led_2<=seg[4]; end 1'd5:begin seg_led_1<=seg[0];seg_led_2<=seg[5]; end 1'd6:begin seg_led_1<=seg[0];seg_led_2<=seg[6]; end 1'd7:begin seg_led_1<=seg[0];seg_led_2<=seg[7]; end 1'd8:begin seg_led_1<=seg[0];seg_led_2<=seg[8]; end 1'd9:begin seg_led_1<=seg[0];seg_led_2<=seg[9]; end 1'd10:begin seg_led_1<=seg[1];seg_led_2<=seg[0]; end endcase end seg_led_1<=seg[0]; seg_led_2<=seg[0]; end end always @ (posedge clk) begin if(!rst)begin if(k == 0) case(key) 4'd1:begin seg_led_1<=seg[0];seg_led_2<=seg[1]; end 4'd2:begin seg_led_1<=seg[0];seg_led_2<=seg[2]; end 4'd4:begin seg_led_1<=seg[0];seg_led_2<=seg[3]; end 4'd8:begin seg_led_1<=seg[0];seg_led_2<=seg[4]; end endcase end end endmodule 帮我检查一下这段代码的错误
代码存在以下错误:
1. 代码中有多个 always 块,应将其合并为一个 always 块,同时加入对应的敏感信号。
2. 在 always @(posedge clk_divided) 块中,存在一个不必要的赋值 seg_led_1<=seg[0]; seg_led_2<=seg[0];,应该删除。
3. 在 always @(posedge clk) 块中,k 没有初始化,应该在一开始赋值为 0。
4. 在 always @(posedge clk) 块中,case 语句中没有 default 选项,不够健壮,应该加入 default 选项。
5. 在 case 语句中,应该将 4'd1、4'd2、4'd4、4'd8 改成 4'b0001、4'b0010、4'b0100、4'b1000,因为二进制更加易读。
修改后的代码如下所示:
```verilog
module race_game (
input clk,
input rst,
input [3:0]key,
output reg [6:0]seg_led_1,
output reg [6:0]seg_led_2
);
reg clk_divided;
reg [6:0] seg[9:0];
reg [23:0] cnt;
integer k = 0;
localparam PERIOD = 12000000;
always @(posedge clk) begin
if (!rst) begin
cnt <= 0;
clk_divided <= 0;
k <= 0;
end else begin
if (cnt >= PERIOD-1) begin
cnt <= 0;
clk_divided <= ~clk_divided;
end else begin
cnt <= cnt + 1;
end
end
end
always @ (posedge clk_divided) begin
if (!rst) begin
case(k)
10: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[0]; end
9: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[9]; end
8: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[8]; end
7: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[7]; end
6: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[6]; end
5: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[5]; end
4: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[4]; end
3: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[3]; end
2: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[2]; end
1: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[1]; end
0: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[0]; end
endcase
k <= k - 1;
end
end
always @ (posedge clk) begin
if (!rst) begin
k <= 0;
end else begin
if (k == 0) begin
case(key)
4'b0001: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[1]; end
4'b0010: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[2]; end
4'b0100: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[3]; end
4'b1000: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[4]; end
default: begin seg_led_1 <= seg[0]; seg_led_2 <= seg[0]; end
endcase
end
k <= k + 1;
end
end
initial begin
seg[0] = 7'h3f; // 0
seg[1] = 7'h06; // 1
seg[2] = 7'h5b; // 2
seg[3] = 7'h4f; // 3
seg[4] = 7'h66; // 4
seg[5] = 7'h6d; // 5
seg[6] = 7'h7d; // 6
seg[7] = 7'h07; // 7
seg[8] = 7'h7f; // 8
seg[9] = 7'h6f; // 9
end
endmodule
```
always @(posedge clk)begin if(state==2'd2) begin case(encode_data_in[3:0]) 4'd0:decode_data_out_r<=scope_cnt1; 4'd1:decode_data_out_r<=scope_cnt1+scope_cnt2; 4'd2:decode_data_out_r<=scope_cnt1+2*scope_cnt2; 4'd3:decode_data_out_r<=scope_cnt1+3*scope_cnt2; 4'd4:decode_data_out_r<=scope_cnt1+4*scope_cnt2; 4'd5:decode_data_out_r<=scope_cnt1+5*scope_cnt2; 4'd6:decode_data_out_r<=scope_cnt1+6*scope_cnt2; 4'd7:decode_data_out_r<=scope_cnt1+7*scope_cnt2; 4'd8:decode_data_out_r<=scope_cnt1+8*scope_cnt2; 4'd9:decode_data_out_r<=scope_cnt1+9*scope_cnt2; 4'd10:decode_data_out_r<=scope_cnt1+10*scope_cnt2; 4'd11:decode_data_out_r<=scope_cnt1+11*scope_cnt2; 4'd12:decode_data_out_r<=scope_cnt1+12*scope_cnt2; 4'd13:decode_data_out_r<=scope_cnt1+13*scope_cnt2; 4'd14:decode_data_out_r<=scope_cnt1+14*scope_cnt2; 4'd15:decode_data_out_r<=scope_cnt1+15*scope_cnt2; endcase end end
这段代码也是 Verilog HDL 语言的代码,是一个基于时钟上升沿的状态机模块。当时钟上升沿到来时,如果当前状态为 2,则根据输入信号 encode_data_in[3:0] 来计算输出信号 decode_data_out_r 的值。具体来说,如果输入信号的值为 0,则输出信号的值为 scope_cnt1;如果输入信号的值为 1,则输出信号的值为 scope_cnt1+scope_cnt2;如果输入信号的值为 2,则输出信号的值为 scope_cnt1+2*scope_cnt2;如果输入信号的值为 3,则输出信号的值为 scope_cnt1+3*scope_cnt2;如果输入信号的值为 4,则输出信号的值为 scope_cnt1+4*scope_cnt2;如果输入信号的值为 5,则输出信号的值为 scope_cnt1+5*scope_cnt2;如果输入信号的值为 6,则输出信号的值为 scope_cnt1+6*scope_cnt2;如果输入信号的值为 7,则输出信号的值为 scope_cnt1+7*scope_cnt2;如果输入信号的值为 8,则输出信号的值为 scope_cnt1+8*scope_cnt2;如果输入信号的值为 9,则输出信号的值为 scope_cnt1+9*scope_cnt2;如果输入信号的值为 10,则输出信号的值为 scope_cnt1+10*scope_cnt2;如果输入信号的值为 11,则输出信号的值为 scope_cnt1+11*scope_cnt2;如果输入信号的值为 12,则输出信号的值为 scope_cnt1+12*scope_cnt2;如果输入信号的值为 13,则输出信号的值为 scope_cnt1+13*scope_cnt2;如果输入信号的值为 14,则输出信号的值为 scope_cnt1+14*scope_cnt2;如果输入信号的值为 15,则输出信号的值为 scope_cnt1+15*scope_cnt2。如果当前状态不是 2,则不做任何操作,输出信号的值保持不变。
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