C语言单链表节点相加代码

以下是 C 语言单链表节点相加的代码：

#include <stdio.h>
#include <stdlib.h>

struct ListNode {
    int val;
    struct ListNode *next;
};

struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2){
    struct ListNode *head = NULL, *tail = NULL;
    int carry = 0;
    while (l1 || l2 || carry) {
        int sum = carry;
        if (l1) {
            sum += l1->val;
            l1 = l1->next;
        }
        if (l2) {
            sum += l2->val;
            l2 = l2->next;
        }
        struct ListNode *node = (struct ListNode*)malloc(sizeof(struct ListNode));
        node->val = sum % 10;
        node->next = NULL;
        carry = sum / 10;
        if (!head) {
            head = tail = node;
        } else {
            tail->next = node;
            tail = node;
        }
    }
    return head;
}

int main() {
    struct ListNode *l1 = (struct ListNode*)malloc(sizeof(struct ListNode));
    l1->val = 2;
    l1->next = (struct ListNode*)malloc(sizeof(struct ListNode));
    l1->next->val = 4;
    l1->next->next = (struct ListNode*)malloc(sizeof(struct ListNode));
    l1->next->next->val = 3;
    l1->next->next->next = NULL;

    struct ListNode *l2 = (struct ListNode*)malloc(sizeof(struct ListNode));
    l2->val = 5;
    l2->next = (struct ListNode*)malloc(sizeof(struct ListNode));
    l2->next->val = 6;
    l2->next->next = (struct ListNode*)malloc(sizeof(struct ListNode));
    l2->next->next->val = 4;
    l2->next->next->next = NULL;

    struct ListNode *result = addTwoNumbers(l1, l2);
    while (result) {
        printf("%d ", result->val);
        result = result->next;
    }
    printf("\n");

    return 0;
}

以上是 C 语言单链表节点相加的代码，希望能对你有所帮助。