liang-barsky算法c语言
时间: 2024-01-05 07:02:39 浏览: 94
C语言的算法
以下是 Liang-Barsky 算法的 C 语言实现:
```c
#include <stdio.h>
void LiangBarsky(int x1, int y1, int x2, int y2, int xmin, int ymin, int xmax, int ymax)
{
int dx = x2 - x1;
int dy = y2 - y1;
float p1 = -dx;
float p2 = dx;
float p3 = -dy;
float p4 = dy;
float q1 = x1 - xmin;
float q2 = xmax - x1;
float q3 = y1 - ymin;
float q4 = ymax - y1;
float posarr[5], negarr[5];
int posind = 1, negind = 1;
posarr[0] = 1;
negarr[0] = 0;
if ((p1 == 0 && q1 < 0) || (p3 == 0 && q3 < 0))
{
printf("Line is outside the clipping window\n");
return;
}
if (p1 != 0)
{
float r1 = q1 / p1;
float r2 = q2 / p2;
if (p1 < 0)
{
negarr[negind++] = r1;
posarr[posind++] = r2;
}
else
{
negarr[negind++] = r2;
posarr[posind++] = r1;
}
}
if (p3 != 0)
{
float r3 = q3 / p3;
float r4 = q4 / p4;
if (p3 < 0)
{
negarr[negind++] = r3;
posarr[posind++] = r4;
}
else
{
negarr[negind++] = r4;
posarr[posind++] = r3;
}
}
float xn1, yn1, xn2, yn2;
float rn1 = 0, rn2 = 1;
for (int i = 1; i < posind; i++)
{
float rn = posarr[i];
if (rn < rn2)
{
rn2 = rn;
}
}
for (int i = 1; i < negind; i++)
{
float rn = negarr[i];
if (rn > rn1)
{
rn1 = rn;
}
}
xn1 = x1 + rn1 * dx;
yn1 = y1 + rn1 * dy;
xn2 = x1 + rn2 * dx;
yn2 = y1 + rn2 * dy;
printf("The coordinates of the clipped line are: (%.2f, %.2f) and (%.2f, %.2f)\n", xn1, yn1, xn2, yn2);
}
int main()
{
int x1 = 50, y1 = 50, x2 = 200, y2 = 200;
int xmin = 100, ymin = 100, xmax = 300, ymax = 300;
LiangBarsky(x1, y1, x2, y2, xmin, ymin, xmax, ymax);
return 0;
}
```
这个程序假设输入的线段的起点和终点坐标分别为 (x1, y1) 和 (x2, y2),裁剪窗口的四个边界坐标分别为 xmin, ymin, xmax 和 ymax。函数 `LiangBarsky` 的输出为经过裁剪后的线段的两个端点的坐标。
阅读全文