n=input() m=int(input()) for i in range(0,m): a,b,c,d=map(str,input().split()) p=int(a) q=int(b) s=n[p:q:1] n=n.replace(s,"") t=n.find(d) z=n[0:t:1] x=n[t:len(n):1] w=z+s+x print(w)修改错误
时间: 2023-09-02 19:09:33 浏览: 53
好的,我看出来了,你需要在代码前面加上一个空格或者四个空格才能表示为代码格式。这里是修改后的代码:
```python
n = input()
m = int(input())
for i in range(0, m):
a, b, c, d = map(str, input().split())
p = int(a)
q = int(b)
s = n[p:q+1]
n = n.replace(s, "")
t = n.find(d)
z = n[0:t]
x = n[t:len(n)]
w = z + s + x
print(w)
```
注意到,在第 8 行中,我们将 `q` 加了一,这是因为在 Python 中,字符串切片的区间是左闭右开的,即 `[p, q)`,所以需要将 `q` 加一才能得到正确的子串。
相关问题
n = int(input()) dic = {} for i in range(n): input()
这段代码中,你使用了一个字典 `dic` 来存储一些输入的内容,但是在循环中并没有对字典进行任何操作。根据你的代码,我猜测你可能想要在循环中将输入的内容存储到字典中。以下是一个修改后的示例代码:
```python
n = int(input())
dic = {}
for i in range(n):
value = input()
dic[i] = value
print(dic)
```
在上面的代码中,我们首先获取一个整数 `n` 的输入,表示需要输入的次数。然后,我们创建一个空字典 `dic`。在循环中,我们使用 `input()` 函数获取用户输入的内容,并将其存储到字典中,其中键为循环变量 `i` 的值。最后,我们打印出字典的内容。
你可以根据需要修改代码来适应你的具体需求。
sum=0 m,n=int(input()) for i in range(m,n+1): sum += i print(sum)
This code appears to have syntax errors and does not perform any meaningful operation. Here is a corrected version that sums up all the integers between two given numbers:
```
m = int(input("Enter the start number: "))
n = int(input("Enter the end number: "))
sum = 0
for i in range(m, n+1):
sum += i
print("The sum of all integers between", m, "and", n, "is:", sum)
```
This code prompts the user to input the start and end numbers, initializes a sum variable to 0, and then uses a for loop to iterate over all the integers between the start and end numbers (inclusive). On each iteration, the current integer is added to the sum. Finally, the sum is printed out with a descriptive message.