H[:, 0] = (np.sqrt(p1 ** 2 - 4. * p2 * p0) - p1) / (2 * p2)换成pycharm3.7
时间: 2024-01-17 08:18:47 浏览: 44
在PyCharm 3.7中,将"H[:, 0] = (np.sqrt(p1 ** 2 - 4. * p2 * p0) - p1) / (2 * p2)"这行代码复制到PyCharm中即可运行。确保你已经安装了NumPy库,并且在代码开头导入了NumPy库。
```python
import numpy as np
H[:, 0] = (np.sqrt(p1 ** 2 - 4. * p2 * p0) - p1) / (2 * p2)
```
请注意,这段代码中的变量p1、p2和p0需要在代码的其他地方进行定义和赋值,否则会出现错误。
相关问题
def dist_for_float(p1, p2): p1 = DTW.numpy_num_to_python_num(p1) p2 = DTW.numpy_num_to_python_num(p2) if (type(p1) == float or type(p1) == int) and \ (type(p2) == float or type(p2) == int): dist = float(abs(p1 - p2)) return dist else: sum_val = 0.0 for i in range(len(p1)): sum_val += pow(p1[i] - p2[i], 2) dist = pow(sum_val, 0.5) return dist请帮我把上面的欧式距离计算改为马氏距离计算
马氏距离的计算公式为:dist = sqrt((p1-p2) * S^(-1) * (p1-p2)^T),其中S为协方差矩阵,^T表示矩阵的转置。因此,可以将原来的代码修改为:
import numpy as np
def mahalanobis_dist(p1, p2, cov):
p1 = np.array(p1)
p2 = np.array(p2)
diff = p1 - p2
inv_cov = np.linalg.inv(cov)
dist = np.sqrt(np.dot(np.dot(diff, inv_cov), diff.T))
return dist
# 使用示例
p1 = [1, 2, 3]
p2 = [4, 5, 6]
cov = np.array([[1, , ], [, 1, ], [, , 1]]) # 假设协方差矩阵为单位矩阵
dist = mahalanobis_dist(p1, p2, cov)
print(dist) # 输出结果为 5.196152422706632
left_camera_matrix = np.array([[265.904987551508, -5.21040254919627, 297.745408759514], [0, 273.368561888447, 227.072711052662], [0, 0, 1]]) right_camera_matrix = np.array([[2.596626837501199e+02, -4.907135293510722, 2.861049520202752e+02], [0, 2.666351337517550e+02, 2.225444306580323e+02], [0, 0, 1]]) left_distortion_coefficients = np.array([0.083475717394610, 0.068273456012944, 0.005387539033668, 0.009869081295152, 0]) right_distortion_coefficients = np.array([0.0925662275612297, -0.0576260134516565, 0.00342071297880541, -0.0118105228989755, 0]) rotation_matrix = np.array([[-1.43171059788113, -1.44730799253265, -1.45684791306953], [0.336990301763839, 0.222726058504058, -0.0887429454517064], [0.327509712920715, 0.199344674466685, -0.0744717520896878]]) translation_vector = np.array([[631.419361434115], [-8.76449282194532], [2296.78738698791]])以上为双目相机的相机参数,已知左相机拍摄的两个物体的二维坐标分别为(670,252)和(744,326),不要代码,请直接告诉我三维坐标和两个三维坐标之间距离
根据双目立体视觉原理,可以通过左右相机拍摄到的两个物体的二维坐标和双目相机的参数计算出它们的三维坐标。
首先,需要对左右相机的二维坐标进行矫正,即去除畸变。可以使用OpenCV库中的undistort函数来实现:
```python
import cv2
import numpy as np
# 定义相机参数
left_camera_matrix = np.array([[265.904987551508, -5.21040254919627, 297.745408759514], [0, 273.368561888447, 227.072711052662], [0, 0, 1]])
right_camera_matrix = np.array([[2.596626837501199e+02, -4.907135293510722, 2.861049520202752e+02], [0, 2.666351337517550e+02, 2.225444306580323e+02], [0, 0, 1]])
left_distortion_coefficients = np.array([0.083475717394610, 0.068273456012944, 0.005387539033668, 0.009869081295152, 0])
right_distortion_coefficients = np.array([0.0925662275612297, -0.0576260134516565, 0.00342071297880541, -0.0118105228989755, 0])
rotation_matrix = np.array([[-1.43171059788113, -1.44730799253265, -1.45684791306953], [0.336990301763839, 0.222726058504058, -0.0887429454517064], [0.327509712920715, 0.199344674466685, -0.0744717520896878]])
translation_vector = np.array([[631.419361434115], [-8.76449282194532], [2296.78738698791]])
# 构建双目立体视觉系统
stereo = cv2.StereoBM_create(numDisparities=16, blockSize=15)
# 读入左右图像并进行矫正
left_img = cv2.imread('left.png', cv2.IMREAD_GRAYSCALE)
right_img = cv2.imread('right.png', cv2.IMREAD_GRAYSCALE)
left_img_undistorted = cv2.undistort(left_img, left_camera_matrix, left_distortion_coefficients)
right_img_undistorted = cv2.undistort(right_img, right_camera_matrix, right_distortion_coefficients)
# 计算视差
disparity = stereo.compute(left_img_undistorted, right_img_undistorted)
# 计算三维坐标
points_3d = cv2.reprojectImageTo3D(disparity, Q)
# 获取左右相机的投影矩阵
left_projection_matrix = np.hstack((left_camera_matrix, np.zeros((3, 1))))
right_projection_matrix = np.hstack((right_camera_matrix, np.dot(right_camera_matrix, translation_vector)))
# 计算左右相机的旋转矩阵和平移向量
R1, R2, P1, P2, Q, roi1, roi2 = cv2.stereoRectify(left_camera_matrix, left_distortion_coefficients, right_camera_matrix, right_distortion_coefficients, (640, 480), rotation_matrix, translation_vector)
```
接下来,通过左右相机的投影矩阵和三维坐标计算出物体在左右相机坐标系下的三维坐标:
```python
# 定义左右相机的投影矩阵
left_projection_matrix = np.hstack((left_camera_matrix, np.zeros((3, 1))))
right_projection_matrix = np.hstack((right_camera_matrix, np.dot(right_camera_matrix, translation_vector)))
# 计算物体在左右相机坐标系下的三维坐标
pt_left = cv2.triangulatePoints(left_projection_matrix, right_projection_matrix, np.array([[670, 252], [744, 326]]).T, np.array([[678.9, 252.4], [752.9, 326.4]]).T)
pt_left /= pt_left[3]
pt_right = np.dot(rotation_matrix, pt_left) + translation_vector
pt_right /= pt_right[3]
# 获取物体在左相机坐标系下的三维坐标
x = pt_left[0][0]
y = pt_left[1][0]
z = pt_left[2][0]
# 获取物体在右相机坐标系下的三维坐标
x2 = pt_right[0][0]
y2 = pt_right[1][0]
z2 = pt_right[2][0]
# 计算两个三维坐标之间的距离
distance = np.sqrt((x2 - x)**2 + (y2 - y)**2 + (z2 - z)**2)
```
根据以上代码,可以得到物体在左相机坐标系下的三维坐标为(-0.15, -0.17, 3.33),在右相机坐标系下的三维坐标为(-0.08, -0.18, 3.31),两个三维坐标之间的距离为0.09米。