Write a program which reads an integer and prints sum of its digits.c++
时间: 2024-10-14 09:06:57 浏览: 5
当你想要编写一个C++程序,用于读取一个整数并计算其各个数字之和,你可以参考以下步骤和代码示例:
```cpp
#include <iostream>
// 函数用于获取一个整数的各位数字之和
int sumOfDigits(int num) {
int sum = 0;
while (num != 0) {
sum += num % 10; // 取余数得到最后一位,加到总和上
num /= 10; // 除以10去掉最后一位
}
return sum;
}
int main() {
int input;
std::cout << "请输入一个整数: ";
std::cin >> input;
// 计算输入整数的每一位数字之和
int digitSum = sumOfDigits(input);
std::cout << "该整数各位数字之和为: " << digitSum << std::endl;
return 0;
}
```
在这个程序中,首先定义了一个函数`sumOfDigits`接受一个整数作为输入,并通过不断地取余数和整除的方式逐位累加数字。然后,在`main`函数中,从用户那里接收输入,调用这个函数并将结果输出。
相关问题
write a Java program called SumOfDigits which reads an integer between 0 and 1000 and adds all the digits in the integer.
Sure, here's the Java program to solve your problem:
```
import java.util.Scanner;
public class SumOfDigits {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter an integer between 0 and 1000: ");
int num = input.nextInt();
int sum = 0;
while (num > 0) {
sum += num % 10;
num /= 10;
}
System.out.println("The sum of the digits is " + sum);
}
}
```
This program prompts the user to enter an integer between 0 and 1000 and then uses a while loop to add up all the digits in the integer. The program then prints out the sum of the digits.
write a c program that reads a positive integer,and prints all its factors
#include <stdio.h>
int main() {
int num, i;
printf("Enter a positive integer: ");
scanf("%d", &num);
printf("Factors of %d are: ", num);
for (i = 1; i <= num; ++i) {
if (num % i == 0) {
printf("%d ", i);
}
}
return 0;
}