八数码问题python代码深度优先
时间: 2023-11-12 09:58:09 浏览: 142
好的,以下是八数码问题的深度优先搜索的Python代码:
```python
def dfs(start, target):
stack = [(start, "")]
visited = set()
while stack:
node, path = stack.pop()
if node == target:
return path
if node in visited:
continue
visited.add(node)
for move, delta in moves.items():
next_node = apply_move(node, delta)
if next_node is not None:
stack.append((next_node, path + move))
return None
def apply_move(node, delta):
x, y = node.index("0") // 3, node.index("0") % 3
dx, dy = delta
nx, ny = x + dx, y + dy
if 0 <= nx < 3 and 0 <= ny < 3:
i, j = nx * 3 + ny, x * 3 + y
return node[:j] + node[i] + node[j+1:i] + "0" + node[i+1:]
else:
return None
moves = {
"U": (-1, 0),
"D": (1, 0),
"L": (0, -1),
"R": (0, 1)
}
start = "123456780"
target = "087654321"
path = dfs(start, target)
print(path)
```
其中,`dfs` 函数实现了深度优先搜索,`apply_move` 函数实现了移动操作,`moves` 字典定义了四个方向的移动,`start` 和 `target` 分别是起始状态和目标状态。
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