x转置Ax对x求偏导
时间: 2023-08-23 10:13:32 浏览: 71
根据引用\[1\]中的解释,当求解x转置Ax对x求偏导时,我们需要将x视为列向量,并对x的每个分量分别求偏导数。然后将这些偏导数整理成一个列向量,与x的形状保持一致。所以,对于x转置Ax对x求偏导,结果应该是一个与x形状相同的列向量。
#### 引用[.reference_title]
- *1* [向量,标量对向量求导数](https://blog.csdn.net/weixin_41230454/article/details/83818225)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v91^insertT0,239^v3^insert_chatgpt"}} ] [.reference_item]
- *2* [线性代数之矩阵偏导](https://blog.csdn.net/shenliang1985/article/details/115671355)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v91^insertT0,239^v3^insert_chatgpt"}} ] [.reference_item]
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