把这段话翻译成中文:Initially, Jordan mentioned that the Pre-Configuration feature was not working, even with both EX920 meshed and connected to the internet. When the testing started I deleted the network and factory reset the devices then powered them off. I created the network in the portal and enabled pre configuration parameters. Powered on the main unit and after a short time the network came online in the portal, we powered on the satellite unit and also came online in the portal. These initial testing show the appropriate behavior. later on, Jordan attempted to recreate the previous test and mentioned it did not work for him, the network remained inactive in the portal. On our next troubleshooting call I followed the exact same previous steps and the network remained inactive in the portal.

时间: 2023-03-06 07:02:56 浏览: 226
首先,乔丹提到,即使EX920互联网拓扑结构连接在网络上,预配置功能也无法正常工作。在测试开始时,我删除了网络,并对设备进行了恢复出厂设置,然后将其关闭。我在门户中创建了网络,并启用了预配置参数。打开主机,短时间内网络就在门户中上线了,我们打开卫星单元,也在门户中上线。这些初始测试表明了适当的行为。后来,乔丹试图重新创建之前的测试,但他说它对他来说不起作用,网络仍然在门户中处于不活动状态。在我们的下一次故障排除电话中,我按照完全相同的步骤,网络仍然在门户中处于不活动状态。
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use Java to achieve that:Write a program to display font sizes Layout It should have: ● In the top: - label for letter “X” - label for font size value ● In the bottom: - button to increase font size - button to decrease font size Desired final look: Functionality Initially, the X label should display an 18 point “X”, and the font size label should display the value “18”. Every time the “increase” button is selected, the font size of the “X” and the value in the font size label should be increased by 1. Every time the “decrease” button is selected, the font size of the “X” and the value in the font size label should be decreased by 1. Make sure that this does not allow negative font sizes.

Sure, here is the Java code to achieve the same functionality: ```java import java.awt.Font; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JPanel; public class FontSizer extends JFrame { private JLabel xLabel; private JLabel fontSizeLabel; private JButton increaseButton; private JButton decreaseButton; private int fontSize; public FontSizer() { super("Font Sizer"); this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); this.setSize(300, 200); // create top panel with "X" label and font size label JPanel topPanel = new JPanel(); this.xLabel = new JLabel("X"); this.fontSize = 18; this.fontSizeLabel = new JLabel(Integer.toString(this.fontSize)); this.fontSizeLabel.setFont(new Font("Helvetica", Font.PLAIN, 14)); topPanel.add(this.xLabel); topPanel.add(this.fontSizeLabel); // create bottom panel with increase and decrease buttons JPanel bottomPanel = new JPanel(); this.increaseButton = new JButton("Increase Font Size"); this.increaseButton.addActionListener(e -> increaseFontSize()); this.decreaseButton = new JButton("Decrease Font Size"); this.decreaseButton.addActionListener(e -> decreaseFontSize()); bottomPanel.add(this.increaseButton); bottomPanel.add(this.decreaseButton); // add panels to main frame this.add(topPanel); this.add(bottomPanel, "South"); this.setVisible(true); } private void increaseFontSize() { this.fontSize++; updateFontSize(); } private void decreaseFontSize() { if (this.fontSize > 1) { this.fontSize--; updateFontSize(); } } private void updateFontSize() { this.xLabel.setFont(new Font("Helvetica", Font.PLAIN, this.fontSize)); this.fontSizeLabel.setText(Integer.toString(this.fontSize)); } public static void main(String[] args) { new FontSizer(); } } ``` This Java program creates a window with a label for the letter "X" and a label for the font size value. It also has two buttons at the bottom to increase or decrease the font size. The font size of the "X" label and the font size value label are updated whenever the user clicks on the increase or decrease buttons. To use this program, save the code in a file with a ".java" extension and compile it using a Java compiler. Then, run the program using the Java Virtual Machine (JVM).

Write a program to display font sizes Layout It should have: ● In the top: - label for letter “X” - label for font size value ● In the bottom: - button to increase font size - button to decrease font size Desired final look: Functionality Initially, the X label should display an 18 point “X”, and the font size label should display the value “18”. Every time the “increase” button is selected, the font size of the “X” and the value in the font size label should be increased by 1. Every time the “decrease” button is selected, the font size of the “X” and the value in the font size label should be decreased by 1. Make sure that this does not allow negative font sizes.

Here is an example program written in Java using Swing library to display font sizes: ```java import java.awt.*; import java.awt.event.*; import javax.swing.*; public class FontSizeDisplay extends JFrame { private JLabel xLabel; private JLabel fontSizeLabel; private int fontSize = 18; public FontSizeDisplay() { setTitle("Font Size Display"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); setSize(300, 200); setLocationRelativeTo(null); setLayout(new BorderLayout()); // Top panel with X label and font size label JPanel topPanel = new JPanel(new GridLayout(2, 1)); xLabel = new JLabel("X", SwingConstants.CENTER); xLabel.setFont(new Font("Arial", Font.PLAIN, fontSize)); fontSizeLabel = new JLabel(Integer.toString(fontSize), SwingConstants.CENTER); topPanel.add(xLabel); topPanel.add(fontSizeLabel); add(topPanel, BorderLayout.CENTER); // Bottom panel with increase and decrease buttons JPanel bottomPanel = new JPanel(new GridLayout(1, 2)); JButton increaseButton = new JButton("Increase"); increaseButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { fontSize++; if (fontSize > 0) { xLabel.setFont(new Font("Arial", Font.PLAIN, fontSize)); fontSizeLabel.setText(Integer.toString(fontSize)); } else { fontSize--; } } }); JButton decreaseButton = new JButton("Decrease"); decreaseButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { fontSize--; if (fontSize > 0) { xLabel.setFont(new Font("Arial", Font.PLAIN, fontSize)); fontSizeLabel.setText(Integer.toString(fontSize)); } else { fontSize++; } } }); bottomPanel.add(increaseButton); bottomPanel.add(decreaseButton); add(bottomPanel, BorderLayout.SOUTH); } public static void main(String[] args) { FontSizeDisplay app = new FontSizeDisplay(); app.setVisible(true); } } ``` In this program, we create a JFrame window with a BorderLayout layout. In the center of the window, we create a top panel with X label and font size label, and a bottom panel with increase and decrease buttons. The X label is initially set to font size 18, and the font size label displays the value "18". The increase and decrease buttons have action listeners that update the font size of the X label and the value in the font size label. We also make sure that the font size does not become negative. When you run this program, you should see a window with an X label and a font size label in the center, and increase and decrease buttons at the bottom. Clicking the increase button will increase the font size of the X label and the value in the font size label by 1, and clicking the decrease button will decrease the font size by 1.
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Create a function pixel_flip(lst, orig_lst, budget, results, i=0) that uses recursion to generate all possible new unique images from the input orig_lst, following these rules: • The input lst is the current list being processed. Initially, this will be the same as orig_lst which is the original flattened image. • The input budget represents the number of pixels that can still be flipped. When the budget reaches 0, no more pixels can be flipped. • The input results is a list of resulting flattened images with flipped pixels. Initially, this will be an empty list. • The input i represents the index of the pixel being processed, by default set to 0, which is used to drive the recursive function towards its base case (i.e., initially starting from i=0). At termination of the function, the argument results should contain all possibilities of the input orig_lst by only flipping pixels from 0 to 1 under both the budget and the adjacency constraints. fill code at #TODO def pixel_flip(lst: list[int], orig_lst: list[int], budget: int, results: list, i: int = 0) -> None: """ Uses recursion to generate all possibilities of flipped arrays where a pixel was a 0 and there was an adjacent pixel with the value of 1. :param lst: 1D list of integers representing a flattened image . :param orig_lst: 1D list of integers representing the original flattened image. :param budget: Integer representing the number of pixels that can be flipped . :param results: List of 1D lists of integers representing all possibilities of flipped arrays, initially empty. :param i: Integer representing the index of the pixel in question. :return: None. """ #TODO

Robert is a famous engineer. One day he was given a task by his boss. The background of the task was the following: Given a map consisting of square blocks. There were three kinds of blocks: Wall, Grass, and Empty. His boss wanted to place as many robots as possible in the map. Each robot held a laser weapon which could shoot to four directions (north, east, south, west) simultaneously. A robot had to stay at the block where it was initially placed all the time and to keep firing all the time. The laser beams certainly could pass the grid of Grass, but could not pass the grid of Wall. A robot could only be placed in an Empty block. Surely the boss would not want to see one robot hurting another. In other words, two robots must not be placed in one line (horizontally or vertically) unless there is a Wall between them. Now that you are such a smart programmer and one of Robert's best friends, He is asking you to help him solving this problem. That is, given the description of a map, compute the maximum number of robots that can be placed in the map. Input The first line contains an integer T (<= 11) which is the number of test cases. For each test case, the first line contains two integers m and n (1<= m, n <=50) which are the row and column sizes of the map. Then m lines follow, each contains n characters of '#', '', or 'o' which represent Wall, Grass, and Empty, respectively. Output For each test case, first output the case number in one line, in the format: "Case :id" where id is the test case number, counting from 1. In the second line just output the maximum number of robots that can be placed in that map.

7.3.1 Suzuki–Kasami Algorithm This algorithm is defined for a completely connected network of processes. It assumes that initially an arbitrary process has the token. A process i that does not have the token but wants to enter its CS broadcasts a request (i, num), where num is sequence number of that request. The algorithm guarantees that eventually process i receives the token. Every process i maintains an array req[0.. n − 1] of integers, where req[j] designates the sequence number of the latest request received from process j. Note that although every process receives a request, only one process (which currently has the token) can grant the token. As a result, some pending requests become stale or outdated. An important issue in this algorithm is to identify and discard these stale requests. To accomplish this, each process uses the following two additional data structures that are passed on with the token by its current holder: • An array last[0.. n − 1] of integers, where last[k] = r implies that during its last visit to its CS, process k has completed its rth trip • A queue Q containing the identifiers of processes with pending requests When a process i receives a request with a sequence number num from process k, it updates req[k] to max(req[k], num), so that req[k] now represents the most recent request from process k. A process holding the token must guarantee (before passing it to another process) that its Q contains the most recent requests. To satisfy this requirement, when a process i receives a token from another process, it executes the following steps: • It copies its num into last[i]. • For each process k, process i retains process k’s name in its local queue Q only if 1 + last[k] = req[k] (this establishes that the request from process k is a recent one). • Process i completes the execution of its CS codes. • If Q is nonempty, then it forwards the token to the process at the head of Q after deleting its entry. To enter the CS, a process sends (n − 1) requests and receives one message containing the token. The total number of messages required to complete one visit to its CS is thus (n − 1) + 1 = n. Readers are referred to [SK85] for a proof of this algorithm理解Suzuki-Kasami算法,并回答如下问题: 算法是如何辨别和丢弃过时的请求的,或者说为什么要求1 + last[k] = req[k]?

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