目标:按数字键 1~9,控制电机转过 1~9 圈; 配合上下键改变转动方向,按向上键后正向转 1~9 圈,向下键则反向转 1~9 圈;左键固定 正转 90 度,右键固定反转 90;Esc 键终止转动。 unsigned char code KeyCodeMap[4][4] = { //矩阵按键编号到标准键盘键码的映射表 { 0x31, 0x32, 0x33, 0x26 }, //数字键1、数字键2、数字键3、向上键 { 0x34, 0x35, 0x36, 0x25 }, //数字键4、数字键5、数字键6、向左键 { 0x37, 0x38, 0x39, 0x28 }, //数字键7、数字键8、数字键9、向下键 { 0x30, 0x1B, 0x0D, 0x27 } //数字键0、ESC键、 回车键、 向右键
时间: 2024-03-13 07:43:16 浏览: 24
以下是一个基于8051单片机的实现,代码中使用了键盘矩阵扫描的方式来获取按键输入。
```c
#include <reg52.h>
#define STEPPER_PORT P0
#define BTN_PORT P1
unsigned char stepperSequence[] = {
0b00001000,
0b00000100,
0b00000010,
0b00000001
};
unsigned char keyCodeMap[4][4] = {
{0x31, 0x32, 0x33, 0x26},
{0x34, 0x35, 0x36, 0x25},
{0x37, 0x38, 0x39, 0x28},
{0x30, 0x1B, 0x0D, 0x27}
};
void delay(unsigned int duration) {
unsigned int i;
for (i = 0; i < duration; i++) {
TH0 = 0;
TL0 = 0;
TR0 = 1;
while (TF0 == 0);
TR0 = 0;
TF0 = 0;
}
}
void rotateClockwise(unsigned char steps) {
unsigned int i, j;
for (i = 0; i < steps; i++) {
for (j = 0; j < 4; j++) {
STEPPER_PORT = stepperSequence[j];
delay(100);
}
}
}
void rotateAnticlockwise(unsigned char steps) {
unsigned int i, j;
for (i = 0; i < steps; i++) {
for (j = 3; j >= 0; j--) {
STEPPER_PORT = stepperSequence[j];
delay(100);
}
}
}
void turnRight() {
STEPPER_PORT = 0b00000001;
delay(1000);
STEPPER_PORT = 0;
}
void turnLeft() {
STEPPER_PORT = 0b00001000;
delay(1000);
STEPPER_PORT = 0;
}
void main() {
unsigned char row = 0, col = 0;
unsigned char btnState = 0, lastBtnState = 0;
unsigned char direction = 1;
unsigned char steps = 1;
while (1) {
// 扫描键盘矩阵
BTN_PORT = 0x0F;
col = BTN_PORT & 0x0F;
BTN_PORT = 0xF0;
row = BTN_PORT & 0xF0;
if (row != 0xF0 && col != 0x0F) {
btnState = keyCodeMap[row >> 4][col >> 4];
} else {
btnState = 0;
}
// 处理按键输入
if (btnState != lastBtnState) {
if (btnState >= 0x31 && btnState <= 0x39) {
steps = btnState - 0x30;
} else if (btnState == 0x26) {
direction = 1;
} else if (btnState == 0x28) {
direction = 0;
} else if (btnState == 0x25) {
turnLeft();
continue;
} else if (btnState == 0x27) {
turnRight();
continue;
} else if (btnState == 0x1B) {
break;
}
if (direction == 1) {
rotateClockwise(steps);
} else {
rotateAnticlockwise(steps);
}
}
lastBtnState = btnState;
}
}
```
上面的代码使用了定时器来实现延时,需要在程序前先初始化定时器。具体的电机驱动代码需要根据使用的电机驱动模块来确定。