python编译1000以内的完数，输出6

以下是 Python 代码实现：

def is_perfect_number(n):
    divisors = [1]
    for i in range(2, int(n/2)+1):
        if n % i == 0:
            divisors.append(i)
    return sum(divisors) == n

for i in range(2, 1001):
    if is_perfect_number(i):
        print(i)

输出为：

6
28
496