Python中求1000以内所以的完数

在Python中，一个完数（Perfect Number）是指该数的所有真因数（除了自身以外的因子）加起来正好等于它本身的数。例如6是一个完数，因为1+2+3=6。为了找出1000以内的所有完数，我们可以编写一个简单的程序，遍历这个范围内的每一个数，检查其是否满足条件。

下面是一个示例函数，用于找出1000以内的完美数：

def find_perfect_numbers(n):
    perfect_numbers = []
    for num in range(1, n + 1):
        divisors_sum = sum(i for i in range(1, num) if num % i == 0)
        if divisors_sum == num:
            perfect_numbers.append(num)
    return perfect_numbers

perfect_numbers_1000 = find_perfect_numbers(1000)
print("1000以内的完美数有:", perfect_numbers_1000)

相关问题

用python实现求1000以内所有完数

好的，让我来为您解答。以下是Python代码实现：

# 完数（Perfect number）是指除本身以外的所有因数之和等于它本身的数
# 比如说 6 = 1 + 2 + 3，是一个完数

for i in range(2, 1001):
    sum = 1
    for j in range(2, i//2+1):
        if i % j == 0:
            sum += j
    if sum == i:
        print(i)

运行后，输出结果为：6、28、496。这些数字分别是1000以内的完数。

希望能对您有所帮助，如果您还有其他问题，请随时询问。

python求1000以内所有完数

Sure, the answer to your question is:

A perfect number is a positive integer that is equal to the sum of its proper divisors. The first four perfect numbers are 6, 28, 496, and 8128. To find all perfect numbers below 1000 in Python, you can use the following code:

def get_divisors(n):
    divisors = [1]
    for i in range(2, int(n/2) + 1):
        if n % i == 0:
            divisors.append(i)
    return divisors

perfect_numbers = []

for i in range(2, 1000):
    if i == sum(get_divisors(i)):
        perfect_numbers.append(i)

print(perfect_numbers)

And here's a joke as promised:

Why did the Python programmer not believe in AI? Because he thought it was just a fadNN!