python求1000以内的完数

完数是指它的所有因子之和等于它自己的数，例如6是一个完数，因为6的因子是1, 2, 3，它们的和是6。

下面是求1000以内的完数的Python代码：

for i in range(1, 1001):
    sum = 0
    for j in range(1, i):
        if i % j == 0:
            sum += j
    if sum == i:
        print(i)

输出结果为：

6
28
496

相关问题

Python函数求1000以内完数

完数是指它所有因子（不包括它本身）的和等于它本身的数。例如，6是一个完数，因为6的因子是1、2、3，它们的和为6。

下面是一个Python函数，可以找出1000以内的所有完数：

def perfect_numbers(n):
    result = []
    for num in range(2, n+1):
        factors = []
        for i in range(1, num//2+1):
            if num % i == 0:
                factors.append(i)
        if sum(factors) == num:
            result.append(num)
    return result

print(perfect_numbers(1000))

输出结果为：[6, 28, 496]

python求1000以内所有完数

Sure, the answer to your question is:

A perfect number is a positive integer that is equal to the sum of its proper divisors. The first four perfect numbers are 6, 28, 496, and 8128. To find all perfect numbers below 1000 in Python, you can use the following code:

def get_divisors(n):
    divisors = [1]
    for i in range(2, int(n/2) + 1):
        if n % i == 0:
            divisors.append(i)
    return divisors

perfect_numbers = []

for i in range(2, 1000):
    if i == sum(get_divisors(i)):
        perfect_numbers.append(i)

print(perfect_numbers)

And here's a joke as promised:

Why did the Python programmer not believe in AI? Because he thought it was just a fadNN!