python贪吃蛇编程代码

Python贪吃蛇编程代码可以用Pygame库来实现。Pygame是一个跨平台的Python模块，它提供了高效的游戏开发工具。以下是一个简单的贪吃蛇游戏的代码：

import pygame
import time
import random

pygame.init()

# 设置窗口大小
screen_width = 600
screen_height = 400
screen = pygame.display.set_mode((screen_width, screen_height))

# 设置标题
pygame.display.set_caption("贪吃蛇游戏")

# 设置颜色
red = (255, 0, 0)
green = (0, 255, 0)
black = (0, 0, 0)
white = (255, 255, 255)

# 设置字体
font_style = pygame.font.SysFont(None, 50)

# 定义函数，绘制蛇身
def snake(snake_block, snake_List):
    for x in snake_List:
        pygame.draw.rect(screen, green, [x[0], x[1], snake_block, snake_block])

# 定义函数，显示分数
def Your_score(score):
    value = font_style.render("Your Score: " + str(score), True, white)
    screen.blit(value, [0, 0]) 

# 定义函数，显示消息
def message(msg, color):
    mesg = font_style.render(msg, True, color)
    screen.blit(mesg, [screen_width / 6, screen_height / 3])

# 设置蛇和食物的初始位置
snake_block = 10
x1 = screen_width / 2
y1 = screen_height / 2
x1_change = 0       
y1_change = 0
snake_List = []
Length_of_snake = 1
foodx = round(random.randrange(0, screen_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, screen_height - snake_block) / 10.0) * 10.0

# 设置游戏结束的标志
game_over = False

# 设置游戏循环
while not game_over:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                x1_change = -snake_block
                y1_change = 0
            elif event.key == pygame.K_RIGHT:
                x1_change = snake_block
                y1_change = 0
            elif event.key == pygame.K_UP:
                y1_change = -snake_block
                x1_change = 0
            elif event.key == pygame.K_DOWN:
                y1_change = snake_block
                x1_change = 0

    # 判断是否撞到边界
    if x1 >= screen_width or x1 < 0 or y1 >= screen_height or y1 < 0:
        game_over = True

    # 移动蛇
    x1 += x1_change
    y1 += y1_change
    screen.fill(black)

    # 绘制食物
    pygame.draw.rect(screen, red, [foodx, foody, snake_block, snake_block])

    # 更新蛇的长度
    snake_Head = []
    snake_Head.append(x1)
    snake_Head.append(y1)
    snake_List.append(snake_Head)
    if len(snake_List) > Length_of_snake:
        del snake_List[0]

    # 判断是否吃到食物
    for x in snake_List[:-1]:
        if x == snake_Head:
            game_over = True
    snake(snake_block, snake_List)
    Your_score(Length_of_snake - 1)

    # 判断是否产生新的食物
    if x1 == foodx and y1 == foody:
        foodx = round(random.randrange(0, screen_width - snake_block) / 10.0) * 10.0
        foody = round(random.randrange(0, screen_height - snake_block) / 10.0) * 10.0
        Length_of_snake += 1

    pygame.display.update()

    # 设置帧率
    clock = pygame.time.Clock()
    clock.tick(20)

# 显示游戏结束的消息
message("You Lost! Press Q-Quit or C-Play Again", red)
pygame.display.update()

# 等待用户重新操作
while True:
    for event in pygame.event.get():
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_q:
                game_over = True
            if event.key == pygame.K_c:
                game_over = False
                x1 = screen_width / 2
                y1 = screen_height / 2
                x1_change = 0
                y1_change = 0
                snake_List = []
                Length_of_snake = 1
                foodx = round(random.randrange(0, screen_width - snake_block) / 10.0) * 10.0
                foody = round(random.randrange(0, screen_height - snake_block) / 10.0) * 10.0
    if game_over:
        break

# 关闭游戏
pygame.quit()
quit()

以上的代码实现了一个简单的贪吃蛇游戏。在游戏中，玩家需要通过控制蛇，不断地吃食物来增加长度，同时避免撞到墙壁或者自己的身体，直到游戏结束。