利用panda解决以下问题：Firstly, input an integer N, which represents a total of N students. Then enter N lines, each containing the student's name, class, exam 1 score, and exam 2 score. Count the average and total scores of each exam for each class, and sort the results by class name before outputting them to the console. Output includes class, score1_mean, score1_sum, score2_mean, score2_sum.

以下是使用 Pandas 解决该问题的代码：

import pandas as pd

# 输入学生人数
N = int(input("请输入学生人数："))

# 输入每个学生的信息
students = []
for i in range(N):
    name, cls, score1, score2 = input().split()
    students.append({
        "name": name,
        "class": cls,
        "score1": int(score1),
        "score2": int(score2)
    })

# 将学生信息转换成 DataFrame
df = pd.DataFrame(students)

# 按班级分组，计算平均分和总分
grouped = df.groupby("class").agg({
    "score1": ["mean", "sum"],
    "score2": ["mean", "sum"]
})

# 对结果进行排序
grouped = grouped.sort_index()

# 输出结果
print(grouped)

运行该程序后，会先要求输入学生人数，然后再输入每个学生的信息。接着，程序会将学生信息转换成 Pandas DataFrame，并按班级分组，计算每个班级每门考试的平均分和总分。最后，程序对结果按班级名称进行排序，并输出到控制台上。

相关问题

利用pandas解决问题：Firstly, input an integer � N, which represents a total of � N students. Then enter � N lines, each containing the student's name, class, exam 1 score, and exam 2 score. Count the average and total scores of each exam for each class, and

以下是用pandas解决该问题的代码实现：

import pandas as pd

# 读取学生信息
n = int(input())
data = []
for i in range(n):
    line = input().split()
    data.append(line)

# 创建DataFrame
df = pd.DataFrame(data, columns=['name', 'class', 'exam1', 'exam2'])
df[['exam1', 'exam2']] = df[['exam1', 'exam2']].astype(float)

# 计算各班级的平均分和总分
result = df.groupby('class').agg({'exam1': ['mean', 'sum'], 'exam2': ['mean', 'sum']})

# 输出结果
print(result)

上述代码首先读取学生信息，然后创建一个DataFrame。接着通过astype函数将考试成绩的数据类型转换为float类型。最后通过groupby函数对班级进行分组，并计算各班级的平均分和总分。最终输出结果。

Firstly, input an integer � N, which represents a total of � N students. Then enter � N lines, each containing the student's name, class, exam 1 score, and exam 2 score. Count the average and total scores of each exam for each class, and sort the results by class name before outputting them to the console. Output includes class, score1_mean, score1_sum, score2_mean, score2_sum.

Sure, I can help you with that. Here's an example Python code that solves the problem you stated:

# Input the total number of students
N = int(input())

# Create a dictionary to store the results for each class
class_results = {}

# Loop through each student and store their results in the dictionary
for i in range(N):
    name, class_name, exam1, exam2 = input().split()
    exam1 = int(exam1)
    exam2 = int(exam2)
    if class_name not in class_results:
        class_results[class_name] = {'exam1_total': 0, 'exam1_count': 0, 'exam2_total': 0, 'exam2_count': 0}
    class_results[class_name]['exam1_total'] += exam1
    class_results[class_name]['exam1_count'] += 1
    class_results[class_name]['exam2_total'] += exam2
    class_results[class_name]['exam2_count'] += 1

# Sort the results by class name
class_names = sorted(class_results.keys())

# Print the results for each class
for class_name in class_names:
    exam1_mean = class_results[class_name]['exam1_total'] / class_results[class_name]['exam1_count']
    exam2_mean = class_results[class_name]['exam2_total'] / class_results[class_name]['exam2_count']
    exam1_sum = class_results[class_name]['exam1_total']
    exam2_sum = class_results[class_name]['exam2_total']
    print(f"{class_name} {exam1_mean:.2f} {exam1_sum} {exam2_mean:.2f} {exam2_sum}")

Here's how you can use this code:

1. Copy and paste the code into a Python file (e.g. `main.py`).
2. Run the Python file using the command `python main.py`.
3. Enter the total number of students when prompted.
4. Enter the details (name, class, exam 1 score, exam 2 score) for each student, one by one.
5. The program will print the results for each class, sorted by class name.

I hope this helps! Let me know if you have any questions.