用c++实现三次样条插值的算法
时间: 2023-11-18 11:03:50 浏览: 314
以下是C语言实现三次样条插值的算法的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define N 100
double x[N], y[N], h[N], b[N], u[N], v[N], z[N], c[N], d[N];
void spline(int n)
{
int i, k;
double p, qn, sig, un;
// step 1
for (i = 1; i < n; i++)
h[i] = x[i] - x[i-1];
// step 2
for (i = 2; i < n; i++)
{
sig = h[i-1] / (h[i-1] + h[i]);
p = sig * u[i-1] + 2.0;
u[i] = (sig - 1.0) / p;
b[i] = (y[i] - y[i-1]) / h[i] - (y[i-1] - y[i-2]) / h[i-1];
b[i] = (6.0 * b[i] / (h[i-1] + h[i]) - sig * b[i-1]) / p;
}
// step 3
qn = 0.0;
un = 0.0;
c[n-1] = 0.0;
for (k = n-2; k >= 1; k--)
{
c[k] = u[k] * c[k+1] + b[k];
z[k] = (c[k+1] - c[k]) / h[k];
qn = (z[k+1] - z[k]) / (h[k] + h[k+1]) - u[k] * qn;
un = u[k] * un + z[k];
}
// step 4
for (i = 1; i < n; i++)
{
d[i] = (c[i] - c[i-1]) / (3.0 * h[i]);
v[i] = 2.0 * (x[i] - x[i-1]) - h[i-1] * d[i-1];
b[i] = (y[i] - y[i-1]) / (x[i] - x[i-1]) - h[i-1] * (c[i-1] + 2.0 * d[i-1]) / 3.0;
a[i] = (c[i-1] - d[i-1] * h[i-1] * h[i-1] - b[i-1] * h[i-1]) / v[i];
}
}
double spline_eval(double xx, int n)
{
int i, j, k;
double dx, y;
j = 0;
k = n - 1;
while (k - j > 1)
{
i = (j + k) >> 1;
if (x[i] > xx)
k = i;
else
j = i;
}
dx = xx - x[j];
y = a[j] + dx * (b[j] + dx * (c[j] + dx * d[j]));
return y;
}
int main(void)
{
int n, i;
double xx, yy;
printf("Enter the number of data points: ");
scanf("%d", &n);
printf("Enter the data points:\n");
for (i = 0; i < n; i++)
scanf("%lf%lf", &x[i], &y[i]);
spline(n);
printf("Enter the point at which to evaluate the spline: ");
scanf("%lf", &xx);
yy = spline_eval(xx, n);
printf("The value of the spline at %g is %g\n", xx, yy);
return 0;
}
```
该代码实现了三次样条插值算法的主要步骤,包括计算 $h_i$、$u_i$、$b_i$、$c_i$、$d_i$ 等参数,并提供了一个函数 `spline_eval` 用于计算给定点的插值结果。在使用该代码时,首先需要输入数据点的数量和坐标,然后调用 `spline` 函数计算插值参数,最后通过调用 `spline_eval` 函数计算给定点的插值结果。
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