用差分进化算法求解香蕉函数最小值的Python代码
时间: 2023-11-27 17:54:29 浏览: 35
以下是使用差分进化算法求解香蕉函数最小值的Python代码:
```python
import numpy as np
# 定义香蕉函数
def banana(x):
return (1-x[0])**2 + 100*(x[1]-x[0]**2)**2
# 定义差分进化算法
def differential_evolution(func, bounds, popsize=20, mutation=0.8, recombination=0.7, maxiter=1000):
# 随机生成初始种群
dimensions = len(bounds)
pop = np.random.rand(popsize, dimensions)
min_b, max_b = np.asarray(bounds).T
diff = np.fabs(min_b - max_b)
pop_denorm = min_b + pop * diff
# 迭代优化
for i in range(maxiter):
# 变异操作
mutant = pop[np.random.randint(0, popsize, popsize), :]
for j in range(popsize):
idxs = np.arange(popsize) != j
a, b, c = mutant[np.random.choice(idxs, 3, replace=False)]
mutant[j] = np.clip(a + mutation * (b - c), 0, 1)
# 交叉操作
cross_points = np.random.rand(popsize, dimensions) < recombination
if not np.any(cross_points):
cross_points[np.random.randint(0, popsize), np.random.randint(0, dimensions)] = True
pop_new = np.where(cross_points, mutant, pop)
# 选择操作
pop_denorm_new = min_b + pop_new * diff
scores = np.asarray([func(ind) for ind in pop_denorm])
scores_new = np.asarray([func(ind) for ind in pop_denorm_new])
idx = scores_new < scores
pop[idx] = pop_new[idx]
# 返回最优解和最优值
return min_b + pop[np.argmin(scores)]
# 定义搜索范围
bounds = [(-10, 10), (-10, 10)]
# 调用差分进化算法求解最小值
result = differential_evolution(banana, bounds)
# 输出结果
print("最小值点:", result)
print("最小值:", banana(result))
```
在上述代码中,首先定义了香蕉函数 `banana(x)`,然后定义了差分进化算法 `differential_evolution()`,其中包括随机生成初始种群、变异操作、交叉操作和选择操作等步骤。最后定义了搜索范围并调用差分进化算法求解最小值,输出结果为最小值点和最小值。