return the number of even ints in the given array.
时间: 2023-07-01 22:24:35 浏览: 49
Sure! Here's a Python function that takes an array of integers and returns the count of even integers:
```python
def count_evens(nums):
count = 0
for num in nums:
if num % 2 == 0:
count += 1
return count
```
You can call this function with an array of integers like this:
```python
nums = [1, 2, 3, 4, 5, 6]
count = count_evens(nums)
print(count) # Output: 3
```
This will output the count of even integers in the `nums` array, which is 3 in this case. Let me know if you have any other questions!
相关问题
Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.
Sure, I can help you with that! Here's a Python code snippet that counts the number of even integers in an array:
```python
def count_even_numbers(arr):
count = 0
for num in arr:
if num % 2 == 0:
count += 1
return count
```
You can call this function with your array as an argument to get the number of even integers in the array. For example:
```python
arr = [1, 2, 3, 4, 5, 6]
count = count_even_numbers(arr)
print(count) # Output: 3
```
In this example, `count` will be equal to 3 because there are three even integers in the array (`2`, `4`, and `6`).
use java Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1. countEvens([2, 1, 2, 3, 4]) → 3 countEvens([2, 2, 0]) → 3 countEvens([1, 3, 5]) → 0
可以使用以下代码来实现:
```java
public int countEvens(int[] nums) {
int count = 0;
for (int i = 0; i < nums.length; i++) {
if (nums[i] % 2 == 0) {
count++;
}
}
return count;
}
```
该方法遍历整个数组,如果当前数字是偶数,则将计数器加1。最后返回计数器的值即为偶数个数。