在opencv中求直线与圆弧的交点用c++实现

在OpenCV中求直线与圆弧的交点可以使用函数cv::intersectConvexConvex()。下面是一个示例代码，可以实现求直线与圆弧的交点：

#include <opencv2/opencv.hpp>
#include <iostream>

using namespace cv;
using namespace std;

int main()
{
    //定义直线和圆弧
    Vec4f line = { 0, 0, 1, 1 }; //直线：(0,0) -> (1,1)
    Point2f center(0.5, 0.5); //圆弧中心
    float radius = 0.5; //圆弧半径
    float startAngle = 45; //圆弧起始角度
    float endAngle = 135; //圆弧结束角度

    //将圆弧转换为多边形，以便使用intersectConvexConvex函数
    vector<Point2f> arcPoints;
    for (float angle = startAngle; angle <= endAngle; angle += 0.1)
    {
        float x = center.x + radius*cos(angle*CV_PI / 180);
        float y = center.y + radius*sin(angle*CV_PI / 180);
        arcPoints.push_back(Point2f(x, y));
    }

    //计算直线和圆弧的交点
    vector<Point2f> intersectionPoints;
    intersectConvexConvex(arcPoints, { line }, intersectionPoints);

    //输出交点
    for (auto point : intersectionPoints)
    {
        cout << "Intersection point: (" << point.x << "," << point.y << ")" << endl;
    }

    return 0;
}