下段程序中的错误double x0=0; double y0=0; double r=0; double x=0; double y=0; double dis=0; printf("输入圆的半径和圆心的坐标:"); scanf("%lf %lf %lf",&r,&x0,&y0); printf("输入一个坐标:\n"); scanf("%lf %lf",&x,&y); dis= sqrt(pow(x-x0,2)+ pow(y-y0,2)); if(dis<=r){ printf("该点在圆内"); } else{ printf("该点在圆外"); }
时间: 2023-06-25 11:07:01 浏览: 98
这段程序没有明显的错误,但是为了提高程序的健壮性,可以加上一些异常处理。
比如输入的半径、圆心坐标、点的坐标应该是正常的实数,如果输入了非数字的字符,程序就会出现错误。可以使用`fgets()`函数读取用户输入的字符串,再使用`sscanf()`函数将字符串转换成实数类型。如果转换失败,就提示用户重新输入。
另外,如果圆心坐标和点的坐标都是 (0,0),计算两点距离的公式会出现除 0 错误。可以在计算前先判断圆心坐标和点的坐标是否相同,如果相同,就直接输出该点在圆内。
下面是增加异常处理和除 0 判断的程序:
```
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int main()
{
char input[100];
double x0 = 0;
double y0 = 0;
double r = 0;
double x = 0;
double y = 0;
double dis = 0;
printf("输入圆的半径和圆心的坐标:");
fgets(input, sizeof(input), stdin);
if(sscanf(input, "%lf %lf %lf", &r, &x0, &y0) != 3) {
printf("输入格式错误,请重新输入!\n");
return 1;
}
printf("输入一个坐标:\n");
fgets(input, sizeof(input), stdin);
if(sscanf(input, "%lf %lf", &x, &y) != 2) {
printf("输入格式错误,请重新输入!\n");
return 1;
}
if(x == x0 && y == y0) {
printf("该点在圆内\n");
return 0;
}
dis = sqrt(pow(x - x0, 2) + pow(y - y0, 2));
if(dis <= r) {
printf("该点在圆内\n");
} else {
printf("该点在圆外\n");
}
return 0;
}
```
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