使用c++计算口袋中有红黄蓝黑白五种颜色球若干个,每次从口袋中去三个不同颜色的球有多少种取法
时间: 2024-05-12 21:16:32 浏览: 15
```c
#include <stdio.h>
int main() {
int red, yellow, blue, black, white;
printf("请输入口袋中各颜色球的数量(用空格隔开):\n");
scanf("%d %d %d %d %d", &red, &yellow, &blue, &black, &white);
int count = 0;
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= yellow; j++) {
for (int k = 1; k <= blue; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= yellow; j++) {
for (int k = 1; k <= black; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= yellow; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= blue; j++) {
for (int k = 1; k <= black; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= blue; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= red; i++) {
for (int j = 1; j <= black; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= yellow; i++) {
for (int j = 1; j <= blue; j++) {
for (int k = 1; k <= black; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= yellow; i++) {
for (int j = 1; j <= blue; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= yellow; i++) {
for (int j = 1; j <= black; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
for (int i = 1; i <= blue; i++) {
for (int j = 1; j <= black; j++) {
for (int k = 1; k <= white; k++) {
if (i != j && i != k && j != k) {
count++;
}
}
}
}
printf("口袋中取出三个不同颜色的球有 %d 种取法。\n", count);
return 0;
}
```
该程序使用了多层嵌套的循环,分别计算从口袋中取出三个不同颜色的球的所有可能性,最后将所有可能性相加得到总数。其中,为了避免重复计数,每次循环都添加了颜色之间不相等的限制条件。
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