用matlab写代码完成以下要求:Ask user to enter positive numbers 10 times, display all the positive numbers that were entered, and an error message if the user entered an incorrect value. Repeat asking until the user finally enters all 10 positive numbers.
时间: 2023-04-06 16:04:35 浏览: 104
我可以回答这个问题。以下是 MATLAB 代码:
```matlab
% 初始化一个空数组来存储用户输入的正数
positive_numbers = [];
% 循环10次,每次要求用户输入一个正数
for i = 1:10
% 提示用户输入
prompt = sprintf('请输入第 %d 个正数:', i);
% 获取用户输入
user_input = input(prompt);
% 判断用户输入是否为正数
if user_input > 0
% 如果是正数,则将其添加到数组中
positive_numbers(end+1) = user_input;
else
% 如果不是正数,则显示错误消息并重新循环
disp('错误:请输入一个正数。');
i = i - 1;
end
end
% 显示用户输入的所有正数
disp('您输入的正数为:');
disp(positive_numbers);
```
用户将被要求输入10个正数,如果输入的不是正数,则会显示错误消息并重新要求输入。最后,程序将显示用户输入的所有正数。
相关问题
Write c++ program. Enter 10 numbers(int) from the keyboard and find the difference between their maximum and minimum values (using a pointer)
Sure! Here's the C++ program that finds the difference between the maximum and minimum values of 10 numbers entered from the keyboard using a pointer:
```c++
#include <iostream>
using namespace std;
int main()
{
int numbers[10];
int *ptr = numbers;
cout << "Enter 10 numbers: " << endl;
for(int i=0; i<10; i++)
{
cin >> *(ptr+i);
}
int max_val = *ptr;
int min_val = *ptr;
for(int i=1; i<10; i++)
{
if(*(ptr+i) > max_val)
{
max_val = *(ptr+i);
}
if(*(ptr+i) < min_val)
{
min_val = *(ptr+i);
}
}
cout << "Difference between maximum and minimum values: " << max_val - min_val << endl;
return 0;
}
```
In this program, we first declare an array of size 10 to hold the input numbers and a pointer to point to the first element of the array. Then, we prompt the user to enter 10 numbers and read them into the array using pointer arithmetic.
Next, we initialize two variables, `max_val` and `min_val`, with the value of the first element of the array. We then loop through the remaining elements of the array, comparing each element with the current maximum and minimum values and updating them accordingly.
Finally, we output the difference between the maximum and minimum values.
Note that we use the dereference operator `*` to access the values of the array elements through the pointer, and the pointer arithmetic operator `+` to move the pointer to the next element of the array.
Receive the ages of the all your family members (between 3 to 6 members) as command line arguments in the format as following (name then age) Monica 12 Daniel 34 Shelley 23 Compute and display the average of the ages that were entered.in java
Here's a Java program that receives the ages of family members as command line arguments and calculates the average age:
```java
public class FamilyAgeAverage {
public static void main(String[] args) {
// Check if there are at least 3 command line arguments
if (args.length < 6 || args.length % 2 != 0) {
System.out.println("Usage: java FamilyAgeAverage name1 age1 name2 age2 ...");
return;
}
// Parse the ages and calculate the average
int sum = 0;
for (int i = 1; i < args.length; i += 2) {
sum += Integer.parseInt(args[i]);
}
double avg = (double)sum / (args.length / 2);
// Print the average age
System.out.printf("The average age of %d family members is %.2f\n", args.length / 2, avg);
}
}
```
To run this program, open a command prompt or terminal, navigate to the directory containing the `FamilyAgeAverage.java` file, and compile it with the command:
```
javac FamilyAgeAverage.java
```
Then run the program with the command:
```
java FamilyAgeAverage Monica 12 Daniel 34 Shelley 23
```
You can replace these names and ages with your own family members' names and ages. The output should be:
```
The average age of 3 family members is 23.00
```
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