您好.您可以用c分别写一个对图片数据的双线性插值和最近邻插值函数吗.
时间: 2024-05-05 22:18:35 浏览: 5
你好!当然可以,以下是两个函数的代码实现:
双线性插值函数:
```
void Bilinear_interpolation(int* dst, int* src, int w, int h, int w_dst, int h_dst)
{
int xscale = (w - 1) * 65536 / w_dst;
int yscale = (h - 1) * 65536 / h_dst;
for(int i = 0; i < h_dst; i++)
{
int int_y = i * yscale / 65536;
int y_diff = i * yscale % 65536;
for(int j = 0; j < w_dst; j++)
{
int int_x = j * xscale / 65536;
int x_diff = j * xscale % 65536;
int A = src[int_y * w + int_x];
int B = src[int_y * w + int_x + 1];
int C = src[(int_y + 1) * w + int_x];
int D = src[(int_y + 1) * w + int_x + 1];
dst[i * w_dst + j] = (A * (65536 - x_diff) * (65536 - y_diff)
+ B * x_diff * (65536 - y_diff)
+ C * y_diff * (65536 - x_diff)
+ D * x_diff * y_diff) / 65536 / 65536;
}
}
}
```
最近邻插值函数:
```
void Nearest_neighbor_interpolation(int* dst, int* src, int w, int h, int w_dst, int h_dst)
{
int xscale = (w - 1) / w_dst + 1;
int yscale = (h - 1) / h_dst + 1;
for(int i = 0; i < h_dst; i++)
{
int int_y = i * yscale;
for(int j = 0; j < w_dst; j++)
{
int int_x = j * xscale;
dst[i * w_dst + j] = src[int_y * w + int_x];
}
}
}
```
希望这能够帮到你。