输入:n*n的矩阵,随机布局的两种节点 输出: 1)调节参数后输出相应的结果 2)需要有界面显示 相关概念: 当不同种族的邻居数目达到一定数目时或者同类种族邻居书目不足给定数目时,就有搬家的动机。 实验需要考察不同阈值下网络的变化。写出代码实现。
时间: 2024-03-26 11:34:28 浏览: 18
好的,我可以为您提供一个基于Python的实现,实现了上述要求。代码如下:
```python
import random
import tkinter as tk
# 定义节点类
class Node:
def __init__(self, x, y, species):
self.x = x
self.y = y
self.species = species
self.neighbors = []
def __str__(self):
return f"({self.x}, {self.y}, {self.species}, {len(self.neighbors)})"
def add_neighbor(self, node):
if node not in self.neighbors:
self.neighbors.append(node)
def remove_neighbor(self, node):
if node in self.neighbors:
self.neighbors.remove(node)
# 定义网络类
class Network:
def __init__(self, n, p, q, threshold1, threshold2):
self.n = n
self.p = p
self.q = q
self.threshold1 = threshold1
self.threshold2 = threshold2
self.nodes = []
self.moves = []
# 初始化节点
for x in range(n):
for y in range(n):
species = random.randint(0, 1)
node = Node(x, y, species)
self.nodes.append(node)
# 连接节点
for i in range(n * n):
for j in range(i + 1, n * n):
node1 = self.nodes[i]
node2 = self.nodes[j]
if abs(node1.x - node2.x) + abs(node1.y - node2.y) == 1:
if node1.species == node2.species:
if random.random() < p:
node1.add_neighbor(node2)
node2.add_neighbor(node1)
else:
if random.random() < q:
node1.add_neighbor(node2)
node2.add_neighbor(node1)
# 计算节点的动机
def calculate_move(self, node):
if len(node.neighbors) < self.threshold2:
return -1
count1 = 0
count2 = 0
for neighbor in node.neighbors:
if neighbor.species == node.species:
count1 += 1
else:
count2 += 1
if count1 < self.threshold1 or count2 < self.threshold1:
return 1
else:
return 0
# 执行节点的动作
def execute_move(self, node):
node.species = 1 - node.species
self.moves.append(node)
# 更新网络
def update_network(self):
random.shuffle(self.nodes)
for node in self.nodes:
move = self.calculate_move(node)
if move == 1:
self.execute_move(node)
# 定义界面类
class GUI:
def __init__(self, network):
self.network = network
# 创建窗口
self.window = tk.Tk()
self.window.title("Network Simulation")
self.window.geometry("600x600")
# 创建画布
self.canvas = tk.Canvas(self.window, bg="white", width=500, height=500)
self.canvas.place(x=50, y=50)
# 创建按钮
self.button1 = tk.Button(self.window, text="Start", font=("Arial", 12), width=10, height=2, command=self.start_simulation)
self.button1.place(x=200, y=10)
self.button2 = tk.Button(self.window, text="Stop", font=("Arial", 12), width=10, height=2, command=self.stop_simulation)
self.button2.place(x=350, y=10)
# 创建参数框
self.frame = tk.Frame(self.window, width=200, height=100)
self.frame.place(x=50, y=550)
self.label1 = tk.Label(self.frame, text="Threshold1: ")
self.label1.grid(row=0, column=0)
self.entry1 = tk.Entry(self.frame)
self.entry1.grid(row=0, column=1)
self.label2 = tk.Label(self.frame, text="Threshold2: ")
self.label2.grid(row=1, column=0)
self.entry2 = tk.Entry(self.frame)
self.entry2.grid(row=1, column=1)
# 初始化网络
self.init_network()
# 初始化网络
def init_network(self):
for node in self.network.nodes:
x1 = node.x * 20 + 50
y1 = node.y * 20 + 50
x2 = x1 + 20
y2 = y1 + 20
color = "red" if node.species == 0 else "blue"
self.canvas.create_rectangle(x1, y1, x2, y2, fill=color)
self.canvas.update()
# 开始模拟
def start_simulation(self):
threshold1 = int(self.entry1.get())
threshold2 = int(self.entry2.get())
self.network.threshold1 = threshold1
self.network.threshold2 = threshold2
self.timer = self.canvas.after(100, self.update_network)
# 停止模拟
def stop_simulation(self):
self.canvas.after_cancel(self.timer)
# 更新网络
def update_network(self):
self.network.update_network()
for node in self.network.moves:
x1 = node.x * 20 + 50
y1 = node.y * 20 + 50
x2 = x1 + 20
y2 = y1 + 20
color = "red" if node.species == 0 else "blue"
self.canvas.create_rectangle(x1, y1, x2, y2, fill=color)
self.canvas.update()
self.network.moves = []
self.timer = self.canvas.after(100, self.update_network)
# 主函数
if __name__ == "__main__":
n = 20
p = 0.8
q = 0.2
threshold1 = 3
threshold2 = 5
network = Network(n, p, q, threshold1, threshold2)
gui = GUI(network)
gui.window.mainloop()
```
这个实现使用了Python的Tkinter库来实现界面的设计,可以通过修改`threshold1`和`threshold2`来调整阈值,从而观察网络的变化。希望我的回答对您有所帮助。